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Mathematics 22 Online
OpenStudy (daniellelovee):

help

OpenStudy (daniellelovee):

how can i know if it is independent or dependent @satellite73

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

if \[P(A|B)=\frac{P(A\cap B)}{P(B)}=P(A)\] then they are "independent" compare \[\frac{P(A\cap B)}{P(B)}\] with \(P(A)\) if they are equal, then independent

OpenStudy (daniellelovee):

i got 1/4

OpenStudy (anonymous):

yeah me too, you mean for \(\frac{P(A\cap B)}{P(B)}\) right?

OpenStudy (daniellelovee):

so 25% is not 10% right?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

therefore NOT independent, which actually means "dependent"

OpenStudy (daniellelovee):

ok thank you :)

OpenStudy (anonymous):

yw

OpenStudy (daniellelovee):

so that would be dependent for a right?

OpenStudy (anonymous):

not sure what you mean "for a"

OpenStudy (daniellelovee):

for P(A)

OpenStudy (anonymous):

ok hold on

OpenStudy (daniellelovee):

or just for A?

OpenStudy (anonymous):

you do not call probabilities independent ore dependent, only sets right BUT you cannot say as set A in independent, that doesn't mean anything you say A and B are independent or A and B are dependent

OpenStudy (daniellelovee):

oh ok so in this case A and B are dependent then thank you :)

OpenStudy (anonymous):

yw

OpenStudy (daniellelovee):

I did them all and I got that none is independent is that correct?

OpenStudy (daniellelovee):

@satellite73

OpenStudy (daniellelovee):

OpenStudy (daniellelovee):

@satellite73

OpenStudy (daniellelovee):

@whpalmer4

OpenStudy (daniellelovee):

@Qwertty123

OpenStudy (qwertty123):

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