Question

0

Answer 1

I was thinking that it can be

x - 4, if x < 0
x - 2, if X > 0

Any ideas on what to do? I'm stuck, I'm able to do it the original and normal version, just not this....

Answer 2

I don't think that works. It looks like this

Answer 3

you need a function that has a "break" at x = 3.
Use a different function for each part of the domain. One for (-4, 3) and another for (3, ∞)

Answer 4

Hmmm

Mind if you explain a bit on how you go that, that way I can be able to try it?

Won't that contradict the range since it's (-2, ∞)?

Answer 5

I was thinking that the top is three and continuing (looks like an identity function)

Should I try for pieceone

x if x >_ 1

Answer 6

I graphed your two equations, stopping the first one at 0, and starting the second at 0. You're right it does contradict the range, that's one reason it doesn't work.
The other reason is, your domain doesn't have any discontinuities at 0.

Answer 7

wait,

i mean x if x > or equal to 3

Answer 8

wait, nvm that won't do either...

Answer 9

yeah we can do that, but it should be x > 3 instead of ≥ since 3 isn't in the domain

Answer 10

But what about the bottom part, shouldn't it be

x if x > -3

Answer 11

and for the 2nd piece i was thinking

-x if x<-4

Answer 12

That's actually the bottom part. The top part would be from -4 to 3.