Check my work? Central Angles Find the measure of the central angle with a radius of 13 inches and the area of a sector measuring 42.25pi square inches.
\[\frac{ 7605 }{ \frac{ 1 }{ 2 } (13^2)}\] I got this because I translated 42.25pi to degrees (7605)
From there, it should be 90 degrees for the central angle.
@TheSmartOne If you have time?
\(\sf\Large Sector~Area = \frac{\theta}{2}\cdotr^2\) Plugging in the info given: \(\sf\Large 42.25\pi = \frac{\theta}{2}\cdot(13)^2\) Solve for \(\theta\)
I thought sector area was... \[A = \frac{ 1 }{ 2 }r^2\theta\]
If I follow your equation, I'm looking at... 1.57
Which doesn't seem right.
\(\sf\Large Sector~Area = \frac{\theta}{2}\cdot r^2\) Plugging in the info given: \(\sf\Large 42.25\pi = \frac{\theta}{2}\cdot(13)^2\) Solve for \(\theta\)
The formula you stated is the same.
theta/2 * r^2 = 1/2 * theta * r^2 same thing :P
\[84.5\pi=\theta*169\]
\[84.5\pi/169 = \theta\]
I'm still getting 1.57
why are you making it a decimal?
84.5/169 = 845/1690 = 1/2
It's what my calculator says.
Alright. But 1/2 isn't in degrees. and 50 degrees isn't one of my choices.
@Astrophysics if you get the chance.
It's 1/2 pi 0.5* pi
and that's in radians ^
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