Question

Divide.

1. (48x^4 - 6x^3 - 32 x + 4) / (-1 + 8x)

Answer 1

one sec let me do this so i have the answer before i guide you through it

Answer 2

Okay (:

Answer 3

were did you get this question?

Answer 4

A sheet my teacher gave me for homework.

Answer 5

what grade are you in?

Answer 6

Junior

Answer 7

cool :) im a soph but ill be graduating next year too :)

Answer 8

Oh, really? Dang haha

Answer 9

\[48x^4−6x^3−32x+4/−1+8x\]equals\[48x^4−6x^3−32x+4/8x−1\]

Answer 10

can you factor the numerator?

Answer 11

\[48x^4-6x^3-32x+4\]

Answer 12

Hm, I don't know. :/

Answer 13

one sec and ill explain how to

Answer 14

Aight

Answer 15

What is the largest number that divides evenly into \[48x^4\]\[−6x^3\]\[−32x\] and \[44\]?

Answer 16

2

Answer 17

yup

Answer 18

so your greatest common factor is 2

Answer 19

now you are going to divide each term by 2
\[(48x^4/2−6x^3/2−32x/2+4/2)\]

Answer 20

and place (2) on the outside of the parenthesis

Answer 21

2 ( 24x^4 - 3x^3 - 16x + 2 )

Answer 22

\[2(24x^4−3x^3−16x+2)\] is correct

Answer 23

if you place \[
and
\ ] (without any spaces) it makes it an actual equation and easier to read

Answer 24

Ohh, okay

Answer 25

\[2(24x^4-3x^3-16x+2)]/

Answer 26

Wat, lol. Didn't work

Answer 27

\[2(24x^4-3x^3-16x+2)\]

Answer 28

Alright, got it

Answer 29

Factor out common terms in the first two terms, then in the last two terms
so \[24x^4\] and \[-3x^3\] have \[3x^3\] as a common term so divide \[3x^3\] on each and place it outside the parenthes

Answer 30

ill do this one you do the next

Answer 31

Aight

Answer 32

\[2x^4/3x^3 = 8x\]

Answer 33

\[-3x^3/3x^3=-1\]

Answer 34

so that piece will be \[3x^3(8x-1)\]

Answer 35

you do \[-16x+2\]

Answer 36

the smallest they can both be divided by is what?

Answer 37

largest* number

Answer 38

Oh, alright

\[2x(8x+1)\] ?

Answer 39

close! really close!

Answer 40

they can both be divided by \[-2\]

Answer 41

so thats going to be outside your parenthesis

Answer 42

\[-16x/-2=?\]
\[-2/2=?\]

Answer 43

ohh okay

\[ -2 x(8-1)\]

Answer 44

SUPER CLOSE!

Answer 45

\[-2(8x-1)\]

Answer 46

\[-16x/-2=8x\] and your number outside the parenthisis will be just \[-2\]

Answer 47

you got it!

Answer 48

Yay lol

Answer 49

so now we have \[2(3x^3(8x−1)−2(8x−1))\]

Answer 50

but because \[(8x-1)\] can be factoed out we will make it look a bit nicer by taking it out and putting it by the two so now all you have is...

Answer 51

\[2(8x−1)(3x^3−2)\]

Answer 52

Ohh, I see

Answer 53

now we place it back into the equation

Answer 54

\[2(8x−1)(3x3−2)/8x−1\]

Answer 55

which simply takes out \[(8x-1)\]

Answer 56

and you are left with this \[2(3x^3-2)\]

Answer 57

Which leaves me with \[6x^3 - 4\] ?

Answer 58

yup ^_^

Answer 59

Ohhh, wow. haha thanks so much

Answer 60

your welcome. took a while but we got it :)

Answer 61

yeah lol now i gotta do 10 more of these -_- ..

Answer 62

i can help some more if you want :)

Answer 63

I'm actually fine, I wanna try to do it on my own, now. Thanks a lot tho!

Answer 64

yeah no problem. if you want to double check your answers tag me :)

Answer 65

okay :)

Answer 66

PM me if you ever want to talk. I kinda enjoyed teaching someone who wanted to learn and didnt just want the answer :)

Answer 67

i had a 54 in teamwork before this problem and now i have a 60 XD

Answer 68

yeah I don't really learn if I just get the answer. And that's great! haha

Answer 69

:) PM me sometime tho

Answer 70

Alright (:

Answer 71

:d

Answer 72

i stck my tounge up not down XD

Answer 73

#TiredWithNoLifeDoesNotMakeForGreatSanity

Answer 74

Lmao xD

Answer 75

i PMed you :)