Question

In ΔDEF shown below, segment DG is an altitude.

What statement is needed to prove that ΔDEF is similar to ΔGED?
Segment EF is a hypotenuse. Angle E is congruent to itself. Segment ED is shorter than segment EF. Segment EF is intersected by segment DG.

Answer 1

i think the answer is segment EF is intersected by segment DG.

I know that its not Segment EF is a hypotenuse

Answer 2

@Zale101

Answer 3

am I correct?

Answer 4

@rockstar0765 @RhondaSommer

Answer 5

why am i here?

Answer 6

can you check this for me?

Answer 7

sorry; i never liked these and resented doing em; try @tkhunny

Answer 8

i think i could maybe help

Answer 9

maybe.... it's been awhile

Answer 10

@word2 I believe this is right but could you explain to me how you got your decision?
to see if you did anything wrong

Answer 11

If DG is an Altitude, then DGE is a Right Angle and the three triangles thus defined are all similar to each other. Many things can be stated after that.

Answer 12

to be honest I took a guess , I original thought it was Segment EF is a hypotenuse because They are right angle triangles therefore through Pythagoras theorem, they are similar. I also thought it was the first one because a "hypotenuse" implies the triangle is right triangle. They don't use hypotenuse on the regular triangles

Answer 13

DF, EF, and ED all can be an hypotenuse. It depends on which of the similar triangles you are talking about.

Answer 14

I'm confused... I need to see what statement is needed to prove that ΔDEF is similar to ΔGED?