Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of sin x° and cos y° share?
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for this you need to remember that sine, for a right triangle, is "opposite over hypotenuse"
alrighty
what is the length of the side opposite angle \(x\)?
in this case we,re trying to find the value of sin x and cos y
yes, lets find \(\sin(x)\) first length of side opposite angle \(x\) is ?
so it would be 8 divided by an unknwon number which in this case is the hypoteneuse
@satellite73
it is not unknown
you find it by using pythagoras, if you have not memorized this particular right triangle yet
im sorry what is that? math has never been my strong suit
@satellite73
\[a^2+b^2=c^2\] for a right triangle with legs \(a,b\) and hypotenuse \(c\)
ah okay, let me write that down
@satellite73 so \[x ^{2}+y ^{2}= z ^{2}\]
no in your case \[15^2+8^2=c^2\]
ohh i see
in your case \(x\) and \(y\) are supposed to represent angles, the sides are 8 and 15
alright now i solve for the equation correct?
@satellite73 so 289 squared?
Sorry if im far off and do i need to constantly add your name for a reply or do you still get them?
15 times 15 is 225, 8 times 8 is 64
it is \[15^2+8^2=c^2\] so \[289=c^2\] but you want \(c\) so take the square root of 289
ahh
so 17 squared???
no just 17
ok
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So that is the new figure given after solving that equation. Now we can solve for sin x and cos y???
at the risk of repeating myself, since is "opposite over hypotenuse"
ok lol so 8 divided by 17
yeah, but don't divide, just write \[\sin(x)=\frac{8}{17}\]
alright i wrote it down
would it turn out to be 17 Sin(x) = 8
hello @mathmale
just incase its lagging, im going to refresh page real quick
Valid approach. An alternative approach would be to recognize that x and y are "complementary" angles, meaning that their sum is 90 degrees. They have this property: sin x = cos y. Another alternative: Focus on the side of length 8. 8=17cos y. But also, 8=17 sin x. Thus, sin x = cos y.
Hello, thatawayz!
@mathmale but what if they are not complentary? one could be 30, the other 60
Glad you're interested enough to ask a question like that. However, 30 deg. and 60 deg. ARE complementary, so sin 30 = cos 60, cos 30 = sin 60, and so on.
woah, im sorry i just had a major brainfart lol
i was under the assumption that complimentarys had to be both at an equal angle so 45 and 45
clearly not the case lol
alright, @mathmale what is our next step?
You have already found that the hypotenuse has length 17. Therefore, sin x=8/17, and this is the same as cos y, because x and y are complementary angles.
alright so we just solve for each one right?
No; we're done. How would you answer "What relationship do the ratios of sin x° and cos y° share?"
note that sin x is a ratio, as is cos y.
The relationship between the two is that they are both complimentary angles
both would add to 90
that's true. What about the ratios sin x = 8/17 and cos y=8/17?
Both sin x and cos y are equal to ... ??
that must mean they equal the same thing correct?
Yes, and that "same thing" is 8/17. :)
45
Nope. Sorry about that.
We haven't found either of the 2 unknown angles, have we?
If sin x = 8/17, what is x? Use the inverse sine function to answer that. Express your answer in degrees.
no, i think thats what might have thrown me off a bit and was why i was asking extensively about the whole 8/17 thing
answer to 8/17 is 0.47
The 2 legs of the triangle are given, and satellite73 helped you to find the hypotenuse. That's where we get sin x = 8/17. You have divided 8 by 17. No. What we want is the value (measure) of x when sin x = 8/17. \[\sin ^{-1}\frac{ 8 }{ 17 }=?\]
Have you done a similar problem on your calculator? You might need to set the MODE to 'degrees.'
ahh, no need i have a ti84 plus
hold up, let me grab it real quick
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