Write a polynomilal function in standard form with the given zeros. 1. x = -1, 3, 4
A zero of 'a' means a factor of (x-a). Do that three times. Go!
1, -3, -4?
Yes, those are the zeros. Now, create the corresponding factors.
Yeah i'm not too sure on that lol
It's in my first post. If you have a zero of 'a', make a factor of (x-a). Do it!
Example: If 1 is a "zero" of f(x), then (x-1) is the corresponding factor of f(x). What are the other two factors?
(x-1)(x+3)(x+4)?
Nope, that woul dbe x+, you need x-. Try again.
(x+1)(x-3)(x-4)
More examples If \(\Large \color{red}{10}\) is a root (aka "zero") of the function f(x) then \(\Large x-\color{red}{10}\) is a factor of f(x) If \(\Large \color{blue}{-7}\) is a root of the function f(x) then \(\Large x-(\color{blue}{-7}) = x+7\) is a factor of f(x) Combined, if we know \(\Large \color{red}{10}\) and \(\Large \color{blue}{-7}\) are roots of f(x), then we know that (x-10)(x+7) is a factorization of f(x). If there are more roots, then there are more factors.
@tkhunny so what do i do next?
@tkhunny
You're sort of done. All that is left is the "Standard Form" part. Multiply things out and line up the exponents in descending order.
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