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Mathematics 16 Online
OpenStudy (faolan):

Help pls?? fan n medal ftw https://mvusdk12.owschools.com/media/g_alg02_ccss_2014/5/242a.gif

OpenStudy (faiqraees):

The question isn't complete

OpenStudy (mathmale):

Please provide the instructions that came with this expression. What's your goal? Can you factor one or both of the denominators?

OpenStudy (faolan):

srry....."Combine as indicated by the signs."

OpenStudy (faiqraees):

make the denominators same

OpenStudy (faolan):

how would i do that??

OpenStudy (mathmale):

factor both denominators if possible. Determine the lowest common denominator (LCD). Use the LCD to combine these fractions.

OpenStudy (mathmale):

Hint: factor the denominator of the first fraction first. Do the factors have anything in common with the denominator of the second fraction?

OpenStudy (faolan):

yes. 'y' and 3*3 = 9

OpenStudy (mathmale):

\[y^2-9=y^2-3^2\] is the "difference of two squares." Can y ou factor this? look at y^2 - 3^2 as a whole and come up with 2 factors.

OpenStudy (mathmale):

\[a^2-b^2=(a-b)(a+b)\]

OpenStudy (faolan):

sooooo (y-3)(y+3)??

OpenStudy (mathmale):

Very good. Compare these two factors to the den. of the 2nd fraction. Describe your observations.

OpenStudy (faolan):

cancel out the y+3

OpenStudy (mathmale):

Can't. The idea here is to change the 2nd fraction so that its denom. is the same as that of the first fraction.

OpenStudy (mathmale):

How would you do that? \ On the left you have the den. \[(y-3)(y+3). \]

OpenStudy (mathmale):

On the right you have the denom. y+3. What's missing there? What are you going to do about it?

OpenStudy (faolan):

the right already has the y+3 so all i need to get is the y-3

OpenStudy (faolan):

lol.......ummm.... -1?

OpenStudy (mathmale):

Yes. the 2nd fraction is \[\frac{ 5 }{y+3}\]

OpenStudy (mathmale):

Put that y+3 inside parentheses. Next, multiply numerator (5) and den. (y+3) by (y-3). Results?

OpenStudy (faolan):

if i did it right...... 5/9y? or 5/ y+9

OpenStudy (mathmale):

The second fraction is \[\frac{ 5 }{ y+3 }.\]

OpenStudy (mathmale):

I was asking you to multiply the numerator (5) by (y-3), and also to mult. the denom. (y+3) by (y-3). Please do that now. Results?

OpenStudy (faolan):

ohh srry........ 5y-3/y+9 srry im horrible at math

OpenStudy (mathmale):

Here's what you've typed in: 5y-3/y+9 Here's what we should have: 5(y-3) ----------- (y+3)(y-3) Your numerator would be better if you'd enclose that (y-3) inside parentheses.

OpenStudy (mathmale):

Be certain you understand what I've done here; this is important. The goal was to make the denominators of the 2 fractions the same.

OpenStudy (mathmale):

We now have \[\frac{ 4 }{( y-3)(y+3) }+\frac{ 5(y-3) }{ (y+3)(y-3) }\]

OpenStudy (faolan):

I know they have to b the same, it getting them the same thats the problem for me..... but i understand. I kinda remember going ove the perfect squares and factoring with my teacher

OpenStudy (mathmale):

Are the denominators now the same?

OpenStudy (faolan):

now I just work that out right?

OpenStudy (faolan):

switched around........?

OpenStudy (mathmale):

That switch of order doesn't matter here. The dens. really are the same, mathematically. Can you multiply out 5(y-3)?

OpenStudy (faolan):

would it b 5y-15?

OpenStudy (mathmale):

yes, it would

OpenStudy (mathmale):

and therefore, our \[\frac{ 4 }{( y-3)(y+3) }+\frac{ 5(y-3) }{ (y+3)(y-3) }\]

OpenStudy (mathmale):

becomes\[\frac{ 4 }{( y-3)(y+3) }+\frac{ 5y-15 }{ (y+3)(y-3) }\]

OpenStudy (faolan):

then i add em right?

OpenStudy (mathmale):

Can you now add these 2 fractions together? Yes, you do "add em."

OpenStudy (faolan):

so.... ummmmm 5y-11/...... (y-6)(y+6)?

OpenStudy (mathmale):

Look at the numerators: You have 4 + 5y -15. Yes, you have added these correctly. But why have you changed (y-3)(y+3) to (y-6)(y+6)?

OpenStudy (faolan):

so i dont add those of course they r denominators. srry wasnt thinking those stay the same right?

OpenStudy (mathmale):

the denominators stay exactly the same. Note that \[(y-3)(y+3)=y^2-3^2=y^2-9\]

OpenStudy (mathmale):

Please write your final result here. No need to multiply out the denoms.

OpenStudy (faolan):

5y-11/ (y-3)(y+3) or 5y-11/y^2 -9

OpenStudy (faolan):

the bottom one right?

OpenStudy (mathmale):

It would be right if you'd please enclose the 5y-11 inside parentheses.

OpenStudy (faolan):

(5y-11)/ y^2 -9

OpenStudy (mathmale):

Great. This is the answer you wanted. You have combined the 2 fractions. any questions?

OpenStudy (faolan):

I understand it more than I did earlier thanks!!

OpenStudy (mathmale):

Please practice this. See whether you can copy down the given problem and combine the 2 frac tions into one on your own. Hope to work with you again soon.

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