Question

Need your honest opinion on this project. Please check it aligned with the rubric. I will appreciate it!

MEDAL will be given!!!

Answer 1

The `math.pdf` file is where my project is and `class3levelrubric.pdf` is the rubric. Please check under the Communications column and see if it matched up with the expert area.

Answer 2

@freckles @mathstudent55

Answer 3

*sorry meant to say `classic3levelrubric.pdf`

Answer 4

jimmy can u help me

Answer 5

M still reviewing it and it looks really good so far

Answer 6

sorry to interupt but its supper important ill medal

Answer 7

What

Answer 8

ill also sponcer u to my dads builsness

Answer 9

if your good

Answer 10

Fine

Answer 11

Hit me

Answer 12

@jimmykim How is it?

Answer 13

It looks really good

Answer 14

Are all of the work and explanation sufficient and correct?

Answer 15

Im still looking at it though

Answer 16

Jimmy its urgent please

Answer 17

i just tagged u

Answer 18

@jimmykim u there

Answer 19

yeah

Answer 20

@rebeccaxhawaii can u help too

Answer 21

i really need help

Answer 22

@calculusxy It looks real good, all your formulas and explanations are well written and pronounce

Answer 23

@amitrashok

Answer 24

yah

Answer 25

Thanks @jimmykim

Answer 26

No Problem

Answer 27

@phi

Answer 28

@freckles

Answer 29

@mathmale

Answer 30

@phi How is it?

Answer 31

In the second problem you have a statement
"remember that instead of sin theta = opp/ hyp we need to have sin^-1 = opp / hyp"

you should change the last part to
we will use \( \theta= \sin^{-1} \frac{app}{adj} \)

Answer 32

I don't understand.

Answer 33

Overall it's very good, but the explanation is wordy and thus hard to follow in places.
But writing clearly about math is very hard. (As you know, reading it is bad enough)

Answer 34

Do you think that I will get a 3 out of 3 on this? (According to the rubric)

Answer 35

And another question. Do you mean to say \(\theta = sin^{-1} = \frac{opp}{hyp}\)

Answer 36

this part should be redone

Answer 37

So can I say "we will be using \(\theta = sin^{-1}(\frac{opposite}{hypotenuse})\) "

Answer 38

yes. notice that is different from what you have now.

also, a little further up you say figure out if its sin,cos,tan and then make sure it has a negative one on top

an expert would not write it that way. I would explain it the way you do, but leave that part out, and get the relation
sin theta = 250/2000 = 0.125
then I would say, apply the inverse sin operator to both sides to get
theta = sin^-1 (0.125)
and explain that the inverse sine returns an angle whose sign is 0.125

Answer 39

what do you mean by "who sign is 0.125"?

Answer 40

who's sine is 0.125

Answer 41

okay. can you hang on for like 5 minutes as I revise it? then can you check it again and see if it's alright please?

Answer 42

another question. what do you mean when saying " I would explain it the way you do, but leave that part out"?

Answer 43

I meant explain how to use soh cah toa to choose the correct trig function
sin A = opp/hyp
then show "substituting in the know values" and simplifying
sin A = 250/2000
sin A = 0.125
now you explain to solve for the angle A, use the inverse sin function
A = sin^-1 (0.125)

btw, in case you did not know the inverse sine "undoes" the sin
in other words
\[ \sin^{-1}\left( \sin A \right) = A \]
so we "apply" the inverse sin to both sides:
\[ \sin A = 0.125 \\\sin^{-1}\left( \sin A \right) = \sin^{-1}0.125 \\ A= \sin^{-1}0.125 \\
A= 7.2º\]

Answer 44

okay thanks for clarifying it!