Under certain conditions, there is a 0.015 probability that a randomly selected driver will fail a breathalyzer test. If the police test 10 random drivers, what is the probability of finding at least one driver who fails the test? I know that it would have to be 1 minus the probability that no one fails the test but since they do the test 10 times, when I subtract .015 from 1, i get .985 (the probability they don't fail) so then I put that to the 10th power, but at that point it is larger than 1? am i doing this wrong?
p(1 failure on 1 test) = 0.015 p(1 success on 1 test) = 1 - 0.015 = 0.985 p(10 success on 10 test) = (0.985)^10 < 1 You're not multiplying by 10. You're multiplying by 0.985 < 1.
For some reason, before when I put (.985)^10 into my calculator i got something larger than one, but this time it worked, thank you!
@tkhunny I actually have another question if you could possibly help me?
if a jury list contains 20 men and 20 women, find the probability of selecting 12 members that are all men? Would this be similar: 1-p(no men) ?
No good. Post on another thread. This is a finite population.
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