Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.
\[f(x) = \frac{ 4}{ x } \] and \[g(x)= \frac{ 4 }{ x }\]
\[\large\rm f(\color{orangered}{x})=\frac{4}{\color{orangered}{x}}\]Ok let's try one of the directions, let's plug g into our f,\[\large\rm f(\color{orangered}{g(x)})=\frac{4}{\color{orangered}{g(x)}}\]Replacing g(x) with 4/x in our function gives us,\[\large\rm f(\color{orangered}{g(x)})=\frac{4}{\color{orangered}{\frac4x}}\]
Remember what to do when dividing by a fraction? Have you learned `Keep Change Flip` or something similar perhaps?
yeah
@zepdrix
\(\large\rm \dfrac{a}{\frac{b}{c}}=a\cdot\frac{c}{b}\) `Keep` the numerator the same, `Change` the operation from division to multiplication, `Flip` the bottom fraction.
so it would be \[4 \times \frac{ x }{ 4 }\]
Yes, and then deal with the 4's :) Cancellation, yes?
yes so \[1\times x\]
@zepdrix
Ya so it looks like f(g(x)) = x Good.
thank you @zepdrix
Can you try the other direction on your own? :) It should be very similar.
Oh, actually, it's exactly the same lol
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