Question

Which statement holds true for a skewed histogram showing a distribution of the weights of students in a class?

Answer 1

A. The number of weights on the right side of the mode is equal to the number of weights on the left.

B. The number of weights on the left side of the mean is equal to the number of weights on the right.

C. The mean weight and the median weight will be the same for the distribution.

D. The nature of the skew can be verified by the position of the mean with respect to the median.

E. The nature of the skew can be verified by the position of the mean with respect to the mode.

Answer 2

i think it would be d

Answer 3

The nature of the skew can be verified by
the position of the mean
with respect to the median.

this is correct, if the mean is to the left of the median ... its left skewed; if the mean is to the right of the median, it is right skewed

Answer 4

C is the definiton for a normal distribution, no skew

Answer 5

B and C state the same thing

Answer 6

its simple enough

determine the mean and median of each set, then compare whcih set has the biggest difference between mean and median.

there should be 2 sets that differ in mean and median

Answer 7

A. 2, 3, 3, 4, 4, 4, 5, 5, 6 <-- normal (4,4)

B. 3, 4, 5, 6, 6, 7, 7, 7, 8, 8, 9, 10 <--- out of balance

C. 0.9, 1.0, 1.0, 1.1, 1.1, 1.1, 1.2, 1.2, 1.3 <-- normal (1.1,1.1)

D. 4, 4, 4, 5, 5, 6, 7, 7, 8, 8, 8 <-- normal (6,6)

E. 2, 4, 5, 5, 6, 6, 7, 7, 7, 8, 8, 9, 9, 10 <-- out

Answer 8

A. Mean = 4
B. Mean = 7
C. Mean = 1.1
D Mean= 6
E. Mean= 6.6

Answer 9

429 is fartherest from 7000; so E

Answer 10

E is the correct choice?