Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (hahawowoh):

Can someone show me the equation to get x?

OpenStudy (hahawowoh):

OpenStudy (hahawowoh):

hello?

OpenStudy (mathmale):

To arrive at a possible solution (which would have to be verified before acceptance), I've made some assumptions: 1) that the two lines connecting Q and S and R and T cross at right angles to each other If and only if that's the case, then y=x+3, and, similarly, 3x+2=y+1.

OpenStudy (phi):

haha it's easier (for me anyway) if you post a pdf or screen shot

OpenStudy (phi):

Did they say if the figure is a rhombus ?

OpenStudy (hahawowoh):

Okay :) I know the answer is 1 I just dontknow how to get the answer

OpenStudy (mathmale):

Try solving these two equations for x. Then find y. You'll still need to check whether your x and y "solve" the figure.

OpenStudy (hahawowoh):

Yes the figure is a rhombus. I just dont know how to set up the equation s to find x or y

OpenStudy (mathmale):

phi could ASSUME that the figure is a rhombus and proceed accordingly. @Hahawowoh : So, the problem statement says that the figure is a rhombus? If so, I'm wondering why you didn't share that info with the rest of us up front.

OpenStudy (hahawowoh):

I though you'd know aha

OpenStudy (hahawowoh):

listen I just need help with the equation

OpenStudy (mathmale):

This is not a "haha" matter. It cost me time trying to make reasonable assumptions so that we could get started solving this problem. And I don't like your attitude as expressed in "listen I just need help with the equation." A man would apologize.

OpenStudy (mathmale):

I have already given you hints regarding how to solve this problem. That's as far as I'm going to go.

OpenStudy (phi):

You would look up what the properties of a rhombus are. see http://www.mathsisfun.com/geometry/rhombus.html

OpenStudy (phi):

the property you need to know is that the diagonals bisect (i.e. divide into two equal halves) each other that means you can write down two equations (one for each diagonal) can you try to do that ?

OpenStudy (hahawowoh):

3x+2=y+1

OpenStudy (phi):

ok, and the other one (other diagonal) ?

OpenStudy (hahawowoh):

y=x+3

OpenStudy (phi):

so you have 2 equations and 2 unknowns. If you have an equation for each unknown (and we do here), you can solve for the unknowns. there are two techniques: elimination and substitution

OpenStudy (phi):

3x+2=y+1 y=x+3 as a rule elimination is more systematic (I would use for more than 2 variables) but in this problem notice that you know y is the same as (x+3) (2nd equation) so in the first equation erase the y and put in x+3 instead what is the new equation after you do that ?

OpenStudy (hahawowoh):

3x+2=x+3+1

OpenStudy (phi):

yes, now you "combine like terms" for example 3+1 is easy you get 3x+2= x+4 I would next add -2 to both sides: write -2 on each side, then simplify can you do that ?

OpenStudy (hahawowoh):

Yes, you would get 2x=2 then divide to get 1! thank you so much!!

OpenStudy (phi):

yes

OpenStudy (hahawowoh):

can yo u please help with the Y?

OpenStudy (hahawowoh):

y=x+3 so if x is 1 then y would be 4! i got it!

OpenStudy (phi):

look at the 2nd equation y= x+3 you know x is 1, so you can figure out y

OpenStudy (hahawowoh):

Thank you sosososososo much :)

OpenStudy (phi):

you could also use the first equation and "solve for y" but sometimes it's obvious that one equation is easier to use than the other

OpenStudy (phi):

and if you want to check your answer, you can try x=1 and y=4 in both equations, and both will "work" for example: 3x+2=y+1 3*1+2 = 4+1 3+2= 4+1 5=5 it works

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!