I need some smart people here! A quick exponent question.
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OpenStudy (steve816):
\[9^x = 4\]
what is
\[3^{5x}\]
OpenStudy (anonymous):
your best option here is to take log of both side
OpenStudy (steve816):
then what?
OpenStudy (anonymous):
then solve for x
OpenStudy (steve816):
Doesn't work
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OpenStudy (steve816):
This question is a no calculator question.
OpenStudy (anonymous):
|dw:1454515291773:dw|
OpenStudy (anonymous):
that is the value of x
OpenStudy (steve816):
That is not right...
OpenStudy (steve816):
Please someone verify my answer of 34
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OpenStudy (phi):
9 is also \( 3^2\)
so you can write
\[ 9^x = 4 \\ 3^{2x} = 4 \]
also, you can rewrite
\[ 3^{2x}= \left(3^x\right)^2 \]
and use that to say
\[ \left(3^x\right)^2 =4\]
take the square root of both sides to get
\[ 3^x=2 \]
OpenStudy (phi):
if you want 3^5x raise 3^x to the 5th power
in other words
\[ \left(3^x\right)^5= 3^{5x} \]
and you know 3^x is 2
OpenStudy (steve816):
So is the answer 34?
OpenStudy (anonymous):
how is it not right?
OpenStudy (anonymous):
x=log4/log9=0.63093
now 9^0.63093=4
how is this not right?