Question

Calculus Help!!

Answer 1

So, let's first establish the very sum of defined integrals that apply for our case, the integral from 2 to 6 will be our "variable":
\[\int\limits_{2}^{8}g(x)dx=13 \iff \int\limits_{2}^{6}g(x)dx+\int\limits_{6}^{8}g(x)dx=13\]
Now, we know the value of the integral from 6 to 8 which is (-3) so therefore:
\[\int\limits_{2}^{6}g(x)dx+\int\limits_{6}^{8}g(x)dx=12 \iff \int\limits_{2}^{6}g(x)dx+(-3)=12\]
Having solved for the integral of g(x) from 2 to 6 you will easily be able to calculate our unknown \(2+\int\limits_{2}^{6}g(x)dx\).
Solve for \(\int\limits_{2}^{6}g(x)dx\) on the equality we found:
\[\int\limits_{2}^{6}g(x)dx + (-3)=12\]

Answer 2

type error write 13 in place of 12

Answer 3

13?

Answer 4

Yeah, made a mistake here:
\[\int\limits_{2}^{8}g(x)+(-3)=13\]

Answer 5

\[\int\limits_{2}^{8}g(x)dx=13\]
\[\int\limits_{2}^{6}g(x)dx+\int\limits_{6}^{8}g(x)dx=13\]
\[\int\limits_{2}^{6}g(x)dx+(-3)=13\]
\[\int\limits_{2}^{6}g(x)dx=13+3=16\]
\[2+\int\limits_{2}^{6}g(x)dx=?\]

Answer 6

18

Answer 7

correct.