Each equation given below describes a parabola. Which statement best compares their graphs? x= 5y^2 x=3y^2 a. both parabolas open upward and x=5y^2 is wider than x= 3y^2 b. both parabolas open to the righ and x=3y^2 is wider than x=5y^2 . c. both parabolas open upward and x=3y^2 is wider than x=5y^2 d. both parabolas open to the right and x=5y^2 is wider than x=3y^2
which way do they open?
right @pgpilot326
okay, so which one gets to x = 20 first?
x=5y^2
right, it gets there when y = 2 or -2. the other equation needs more y, meaning it's going to be... wider or skinnier?
wider @pgpilot326
|dw:1454573667512:dw| Comparing the graphs by drawing \(x=15\), we get, For \(x=3y^2\), \(y=\sqrt5,-\sqrt5\) For \(x=5y^2\), \(y=\sqrt3,-\sqrt3\) Thus, \(1)\) Any \(x=ay^2\) is open to the right, if \(a>0\), and open to the left, if \(a<0\). \(2)\) For \(x=ay^2\) and \(x=by^2\), or \(y=ax^2\) and \(y=bx^2\), latter parabola is wider if \(|a|>|b| \) , and latter is slicker if \(|a|<|b| \). \(3)\) \(y=ax^2\) is open upward if \(a>0\) and downward if \(a<0\).
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