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Mathematics 9 Online
OpenStudy (anonymous):

from the line y=3x-10, find the equation of the line that is perpendicular to this line and goes through the point (9, -7)

OpenStudy (kayders1997):

Okay so what does a perpendicular slope have to be compared to the regular slope?

OpenStudy (kayders1997):

What is the slope in the original equation

OpenStudy (anonymous):

It doesn't give an original slope, it just says to find a perpendicular line that will pass through point (9, -7)

OpenStudy (anonymous):

@kayders1997

OpenStudy (kayders1997):

It does thought because the line is y=mx+b where m is slope and b is a y intercept

OpenStudy (anonymous):

I posted the whole question up there, that's why im confused because they didn't give a slope @kayders1997

OpenStudy (kayders1997):

Y=3x-10 is like saying 3 is the slope because y=mx where the m is 3 and m is slope your trying to find the perpendicular slope from that slope

OpenStudy (anonymous):

okay, so can you walk me through it? I really stink at math @kayders1997

OpenStudy (kayders1997):

That's okay, so we know we have a slope of 3 you might want to thing of this as 3/1 when your finding the perpendicular slope you are doing the opposite sing of that original slope and flipping the fraction

OpenStudy (kayders1997):

So I can do an example of the process so you can see how it will work

OpenStudy (anonymous):

that'd be awesome @kayders1997

OpenStudy (kayders1997):

Okay so say you have y=4x-3 you have a slope of 4 and you can think of it as 4/1 so you have to switch sign so you will have -4/1 now you witch the fraction so it would be -1/4 that would be the slope for the perpendicular line now you have to do the same process for this problem

OpenStudy (anonymous):

okay, so how do i graph that as a perpendicular line? @kayders1997

OpenStudy (kayders1997):

Were not quite there yet we still have a few steps did you get the perpendicular slope for the equation?

OpenStudy (anonymous):

No, just that it has to go through (9, -7) @kayders1997

OpenStudy (kayders1997):

Okay so do the process do you want me to go through it with you again but with the real equation?

OpenStudy (anonymous):

Yes please, If you showed all thw work that'd be great :) @kayders1997

OpenStudy (kayders1997):

Do you want me to do the whole problem at once or step by step?

OpenStudy (anonymous):

Step by step :)

OpenStudy (kayders1997):

Y=3x-10 so this is the slope for the perpendicular line, the real answer, so the slope is 3 so think of it as 3/1 so change the sign to a -3/1 and flip the fraction to -1/3 that is the perpendicular slope, does this make sense? :)

OpenStudy (anonymous):

yeah :)

OpenStudy (kayders1997):

Good so now we go to the second part plugging the point (9,-7) into the point slope form do you know what that is?

OpenStudy (anonymous):

So does that make the equation -1 over 3 x - 10?

OpenStudy (kayders1997):

Nope, we have to use the point

OpenStudy (kayders1997):

Do you know the point slope form equation?

OpenStudy (anonymous):

yes

OpenStudy (kayders1997):

Okay so have your coordinate be (x1,y1) (9,-7) so what would youwrite in your equation?

OpenStudy (kayders1997):

If you dont know thats okay I can explain it :)

OpenStudy (anonymous):

haha thanks I'd appreciate it

OpenStudy (kayders1997):

Okay so y-y1=m(x-x1) is the equation, so plug in(9,-7) and m into y1 x1 and m so you will have y--7=-1/3(x-9) Remember the perpendicular slope is -1/3 not 3 Does this make sense?

OpenStudy (kayders1997):

If something isnt making sense just stop me

OpenStudy (anonymous):

yeah, i got it. Thank you :) Can you help me with another question?

OpenStudy (kayders1997):

Sure I might have to eat soon though

OpenStudy (anonymous):

okay cool, Find the point M that cuts the segment with endpoints A(-10, -2) and b(7, 8) into the ratio 2:3

OpenStudy (kayders1997):

I don't know if I can help with this one I havent been in geometry in 2 years

OpenStudy (anonymous):

haha yeah i haven't reviewed in a while so I'm stuck

OpenStudy (kayders1997):

I can maybe try later i gtg

OpenStudy (anonymous):

okay thanks for your help :)

OpenStudy (kayders1997):

No problem :)

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