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Is the function f(x)=1/x even, odd,or neither even or odd? justify your answer?
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\[\large\rm \color{orangered}{f(x)=\frac{1}{x}}\]Can you tell what happens when we plug a negative x into the function?\[\large\rm f(-x)=?\]
we get -1
Mmmmm no. We didn't plug -1 into the function, we plugged -x in place of x.
i dont know i gues -x
\[\large\rm f(-x)=\frac{1}{(-x)}\]Replacing x with -x gives us this, yes?
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The brackets are not necessary I suppose
yes
\[\large\rm f(-x)=-\color{orangered}{\frac{1}{x}}\]Let's pull the negative out front, and recognize that this 1/x is the f(x) function that we started with,\[\large\rm f(-x)=-\color{orangered}{f(x)}\]
Odd functions have this property, f(-x) = -f(x). So we've shown that the function is `odd`.
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