What is the logarithmic form of the equation e4x ≈ 2981?

log4x2981 = e
4 logxe = 2981
ln 4x = 2981
ln 2981 = 4x

Question

What is the logarithmic form of the equation e4x ≈ 2981?

 log4x2981 = e
 4 logxe = 2981
 ln 4x = 2981
 ln 2981 = 4x

anonymous · Answer

@jhonyy9 i need help again

jhonyy9 · Answer

there is e^(4x)  ?

anonymous · Answer

is it going to be In(2981) 4x

anonymous · Answer

yep

anonymous · Answer

e^4x=2981

jhonyy9 · Answer

do you know what is the base of ln

anonymous · Answer

yep i got the answer thank u again...might need so more help

jhonyy9 · Answer

so what will be right sure and how you get it ?

anonymous · Answer

In(2981) 4x

jhonyy9 · Answer

ln has the e like base - hope so much that you know - yes ?

jhonyy9 · Answer

so there are 

e^(4x) = 2981  make logarithm naturale on the both sides and what will get ?

jhonyy9 · Answer

ln e^(4x) = ln 2981

yes ? 

can you continue it ?

jhonyy9 · Answer

so how i have said above the logarithm natural has the base e what mean that ln e =1

so in this case there are 

ln e^(4x) = ln 2981

4xln e = ln 2981    where you know that ln e = 1 than will result 

4x = ln 2981

hope so much that is understandably sure right easy 

yes ?

jhonyy9 · Answer

the last one from these choices 

right ?

jhonyy9 · Answer

sorry just inverse - ok. ?

jhonyy9 · Answer

@Help100