Question

The value V(t) of a $42,000 car after t years that depreciates at 15% per year is given by the formula V(t) = V0(b)t. What is the value of V0 and b, and what is the car's value after 5 years (rounded to the nearest cent)?

Hint: Use the equation b = 1 − r to determine depreciation.
A. V0 = $42,000, b = 0.85, and the value after 5 years is $35,700.00
B. V0 = $42,000, b = 0.15, and the value after 5 years is $3.19
C. V0 = $42,000, b = 0.85, and the value after 5 years is $18,635.62
D. V0 = $42,000, b = 1.15, and the value after 5 years is $84,477.00

Answer 1

@soprano.h.d0816

Answer 2

@RhondaSommer

Answer 3

please help me

Answer 4

Which do you think it is?

Answer 5

i was gonna put D but idk

Answer 6

That sounds about right now that I think about it

Answer 7

really?

Answer 8

Yeah. At first I thought it was C.

Answer 9

why'd you think it was C

Answer 10

maybe I'm wrong

Answer 11

@DanJS do you think I'm right?

Answer 12

I've seen this problem before and I thought the answer was C, I just couldn't remember how I did it first.

Answer 13

tha tis a general exponential function

y(t) = A*b^t

the value at a time t, is the original value to start 'A', times the rate of change for each time

Answer 14

So I was right? lol

Answer 15

lol so the answer is D?

Answer 16

so for each year, it decreases by 15% each year, the value will become 100-15 or 85% of what it was,

each increase in t year, the original value will be multiplied by 0.85

Answer 17

Value at year t

V(t) = 42000*(0.85)^t

Answer 18

So, C

Answer 19

A. V0 = $42,000, b = 0.85, and the value after 5 years is $35,700.00
B. V0 = $42,000, b = 0.15, and the value after 5 years is $3.19
C. V0 = $42,000, b = 0.85, and the value after 5 years is $18,635.62
D. V0 = $42,000, b = 1.15, and the value after 5 years is $84,477.00
which one then?

Answer 20

its either A or C

Answer 21

yeah at year t=6, looks good

Answer 22

V(6) = 45000*(0.85)^6

Answer 23

C

Answer 24

where'd you get 6 from?