Question

Finding area using washer method.

Answer 1

Set up and evaluate an integral for the volume of the solid of revolution obtained by rotating the region bounded by y=x, y=x^2 about the x-axis.

Answer 2

this is finding the volume not area

Answer 3

*Volume. My bad :/

Answer 4

then you are on the right track

Answer 5

The homework website didn't like that set up. I was just wondering where I was messing up at.

Answer 6

ur set up went wrong

Answer 7

(x^2)^2 - (x)^2

Answer 8

Why so @magepker728?

Answer 9

bigger function minus the lower function

Answer 10

since ur boundaries are between 0 and 1 use x= .5, u can see that using y=x^2 =.25 while y=x = .5 we see that y=x^2 is bigger than y=x

Answer 11

.25 is bigger than .5
...?

Answer 12

oops on my phone the other way arround

Answer 13

plus i think the graph u draw is the other way arround

Answer 14

Shouldn't the final answer be pi(2/15)?

Answer 15

your graph looks good.
your integral looks good.

I think mage is just tired XD

Answer 16

red is x

Answer 17

@zepdrix :D check it please

Answer 18

oh yes yes :) red is y=x good call

Answer 19

My bad. I messed up on color coding :D

Answer 20

Regardless, it didn't like the final answer.

Answer 21

No? Hmm

Answer 22

well i got 2/15pi too

Answer 23

I am glad. This problem was killing my confidence.

Answer 24

Well, thanks for the help guys. Y'all have a good night!

Answer 25

wait

Answer 26

Ok

Answer 27

i did work it on a piece of paper but i wont let me uploaded it for some reasons .. but i did it twice and the same answer 2/15pi

Answer 28

@tkhunny

Answer 29

@hartnn

Answer 30

@hartnn can you confirm our findings

Answer 31

yes, everything looks fine.
maybe they wanted the function in some other form....factoring out pi or something....

Answer 32

I tried that out too. It didn't work.

Answer 33

Thanks again everyone for y'alls help!

Answer 34

maybe the answer log is corrupt?