Question

Partial Fractions!! Thank you :)

Answer 1

(2x^3-x^2-2x+13)/((2x-1)(x^2+2))

Answer 2

\[\frac{ 2x ^{3}-x ^{2}-2x+13 }{ (2x-1)(x ^{2}+2) }\]

Answer 3

@Qwertty123 :)

Answer 4

:)

Answer 5

Hai!

Answer 6

hey guys, you mind helping me? I've tried lots of times but each time my answer is different and wrong

Answer 7

Hmm... let me think about it! I will try to figure it out then show you! :D

Answer 8

:)

Answer 9

Um can you hold on... I need to go get a drink! BRB

Answer 10

Since degree of the numerator is not less than degree of the denominator, perform polynomial long division:
Expand divisor: (2x−1)(x2+2)=2x3−x2+4x−2(2x−1)(x2+2)=2x3−x2+4x−2.
Write the problem in a special format:

Answer 11

wait we need to divide it?! oh yeah...improper fractoins can't be partial fractions or smth like that?

Answer 12

Step 1
Divide the leading term of the dividend by the leading term of the divisor: 2x^3
_______= 1
2x^3
Write down calculated result in the upper part of the table.

Answer 13

@Qwertty123 I think I know how to divide it :)

Answer 14

Just wanna confirm that improper fractions cannot be made into partial fractions. If so, that's where I may have gone wrong?

Answer 15

Oh okay..what did you get then?

Answer 16

idk I didn't divide it to make it a proper fraction so I got some pretty weird answers. From here I'm assuming that improper fractions cannot be made into partial fractions????

Answer 17

thats right,
for partial fractions,
the degree of denominator must be strictly greater than the degree of numerator.

If not, we do the long division to achieve that.

Answer 18

you can sometimes avoid long division, like in this case

Answer 19

thanks!