Question

What is the molar ratio of your acid to your base? how did you know?
acid to base titration:
HNO3 + KOH -> KNO3 + H2O

Answer 1

@mazmaz1

Answer 2

@bigbearworthy
can you help me?

Answer 3

@am0x0
can you help me?

Answer 4

@rEdNeCkGiRl101

Answer 5

@Ilovepurple42043 the molar ratio between HNO3 and KOH is 1:2. The ratio between H2SO4 and NaOH is 1:2. Moles NaOH need to neutralize 2 moles of H2SO4 = 2X2= 4

Hope this helps :)

Answer 6

where did the H2SO4 and all that come from? im really bad at chem... do i answer the question by saying all that you did? and ill fan and medal you once we're done :)

Answer 7

my first question is this: is your equation balanced @Ilovepurple42043

Answer 8

im not 100% sure... here...
You have an unknown solution of HNO3 anda solution of 0.50 M KOH. You placed 20 mL of HNO3 into the flask and used 40 mL of KOH from the buret to complete the titration.
then i was told this:
Write the balanced chemical equation for the acid-base titration.
so i put that, did i do it wring?
@Photon336

Answer 9

Yeah so take a look here.

HNO3 + KOH -> KNO3 + H2O

Answer 10

this equation is balanced because we've got the same number of atoms on both sides.

Answer 11

okay. @Photon336 sorry i keep taking forever im babysitting while doing this lol

Answer 12

how do i answer the question that i originially posted? @Photon336

Answer 13

So you know that you have 0.5 M of KOH right? and you used 40 mL of it/

so we can actually find the number of moles of KOH we used.

\[0.5 M = \frac{ 0.5 mol }{ L }~KOH *0.04L = 0.02~mol~NaOH\]

Answer 14

well the key information here is that you completed the titration:

Answer 15

once you've completed your titration the number of moles of titrant and your unknown solution should be equal. so you know that you must also have had 0.02 moles of HNO3 as well Make sense?