Question

Rolle's Theorem cannot be applied to the function f(x) = |x − 3| on the interval [2, 4] because

Answer 1

f is not differentiable on the interval [2, 4]
f(2) ≠ f(4)
All of these
Rolle's theorem can be applied to f(x) = |x − 3| on the interval [2, 4]

Answer 2

Rolle's Theorem only applies is a function is continuous on interval [a,b] and differentiable on interval (a,b). Does this function follow these parameters?

Answer 3

Since it has that corner thingy at origin does that make it not differentiable?

Answer 4

exactly. You can't draw a tangent line to a "corner"

Answer 5

Oh okay. Thank you. cx

Answer 6

Correct. :)

Answer 7

The corner for isn't at the origin; if it was, the interval [2, 4] would be fine. The corner for f(x) = |x − 3| is at x=3. But otherwise good job.

Answer 8

is that all that thing says? for equal values f(a) and f(b) and the function smooth on the interval , then there is a horizontal tangent in the interval? right , the thing has to turn back around to return,