Question

check answer @phi

Answer 1

@pooja195 @tkhunny

Answer 2

I think the answer is 1/10

Answer 3

How?

Answer 4

the idea is
g'(y0) = 1/f'(x0)
f'(x) is 3x^2 -7x^2 +25
y0 is 0
we need x0 (it's not 0), it is 3
so we evaluate 1/f'(3)

Answer 5

1/f'(3) = -1/11, not 1.10

Answer 6

1/10*

Answer 7

nvm, it is 1/10,

Answer 8

hmm I don't see anything wrong there, btw
it boils down to 1/25 assuming it's asking for the "inverse relation" of f(x) and then its derivative and then x = 0

Answer 9

I was plugging into your equation for f'(x) which had 7x^2 instead of 14x

Answer 10

@jdoe0001 I actually did submit 1/25, and 1/10 was the correct answer, but I really don't understand why my method was wrong.

Answer 11

neither do I =(

Answer 12

Weird...I guess I'll just ask my teacher.

Answer 13

Here is a graph that shows the original function (green) , the y=x line, and the inverse which is the red curve (the green curve reflected about the y=x line)
at x=0 I put a point on the green curve i.e. at (0,3)
then I asked geogebra to plot a tangent to the green curve at that point
it found the line y = 0.1x + 3
which shows a slope of 1/10
and the slope of the tangent line is the value of the derivative

Answer 14

Here is the figure

Answer 15

Hmmm....interesting. I don't doubt 1/10 is wrong...I just would like to understand how my method differs.

Answer 16

renaming x to y and then putting in 0 for y does not do what you want.
It seems we have to find the x value that corresponds to y=0
and put that into 1/f'(x)
Finding that value is the hard part. If there is a better way, please let me know.