According to Newton's second law of motion, the force acting on an object varies directly with the object's acceleration. Suppose that a force of 27 N results in acceleration of 3 m/s^2. If the object's acceleration becomes 10 m/s^2, what is the force?

Question

boldjon · Answer

use the first set of numbers to solve for the mass. 

F=ma 

m=f/a 

m= 60/10 = 6kg 

Use the second set of numbers (the objects mass which we have already solved for remains the same) 

F=ma 

a=f/m 

a = 24N/6kg 

a = 4 m/s^2

anonymous · Answer

Well this is more Physics than pure math, but whatevs $$\large \sf F_{net}=m \times a$$ $$\large \sf 27~ N = x ~kg \times 3 ~m/s^{2}$$$$\large \sf x~kg = \frac{27~N}{3~m/s^{2}}$$$$\large \sf x~kg=9~kg$$ So the object is 9 kg. So if we have $$\large \sf F_{Net}= 9~kg \times 10~m/s^{2}$$ what will the Fnet be?

boldjon · Answer

60 = K*10 
K = 6 
24 = 6x 
x = 4m/sec^2

anonymous · Answer

Just ignore boldjon, I think he has a few screws loose lol

boldjon · Answer

-_- i know what i'm doing don't listen to this guy

anonymous · Answer

You're not even doing the right question... lol

boldjon · Answer

yeh sure