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Mathematics 13 Online
OpenStudy (logan13):

What is the median of Variable A? Express answer to one decimal place.

OpenStudy (logan13):

http://prntscr.com/9zl30g

OpenStudy (logan13):

yea was the last one 3.5

OpenStudy (astrophysics):

Nope, last one was \[A=\frac{( 2+2+4+5+6+7+8+9) }{ 8 } = 5.375\]

OpenStudy (logan13):

give me a min

OpenStudy (astrophysics):

Now median here is the middle number once it's sorted out

OpenStudy (logan13):

so this one would be....

OpenStudy (astrophysics):

Put all the numbers in order, and it will be the middle one

OpenStudy (logan13):

so wait what numbers

OpenStudy (astrophysics):

The ones in variable A

OpenStudy (astrophysics):

Horizontal

OpenStudy (astrophysics):

|dw:1454720588030:dw|

OpenStudy (logan13):

so 6.

OpenStudy (logan13):

@Astrophysics

OpenStudy (astrophysics):

\[\huge 1, 2, 4,4,5,6,7,9\]

OpenStudy (logan13):

okay and divide by 8

OpenStudy (astrophysics):

No you're looking for the median, not the mean. Median, you put the numbers in order and it's the middle one, but notice we have an even amount of numbers so we take the middle pair and then find the half way of that.

OpenStudy (logan13):

so we multiply i got 38 when i added those up

OpenStudy (astrophysics):

All you have to do is find the middle number once you've listed all the numbers out for variable A, as I showed above, and since it's even we find the pair in the middle which is 4 and 5, so all we have to do is find the half way between them. \[\huge \frac{ 4+5 }{ 2 } = median\]

OpenStudy (logan13):

9 divided by 2

OpenStudy (logan13):

4.5

OpenStudy (astrophysics):

Yes

OpenStudy (logan13):

so its 4.5

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