Can someone please help me answer this question? I really need help... Solve the following problem using any method of solving systems. CHECK your solutions by substituting your coordinates into BOTH equations and simplifying. Question~ You want to plan a nutritious breakfast. It should supply at least 500 calories or more. Be sure your choices would provide a reasonable breakfast. Suppose you want to have cereal, milk, and one glass of tomato juice. Let c be the number of cups of cereal and m the number of cups of milk. The inequality 102c + 150m + 41 => 500 models the situation.
a) Determine three ordered pairs (c, m) that are solutions of the inequality where 0 <= c < 8 and 0 <= m < 4. b) Graph the inequality. (Assume you can eat partial eggs and drink partial apple juices.)
@jim_thompson5910 @retirEEd could one of y'all help me please?
so you're stuck on part (a) ? or you figured that part out already?
Yes sir/ ma'am, part A is what I don't know what to do, part B I could figure out if I just get help with part A
ok let's say c = 1. So that means you have 1 cup of cereal Plug in c = 1 and then solve the inequality for m. Tell me what you get
0 <= 1 < 8 is that the right way to replace c?
I meant in \[\Large 102c + 150m + 41 \ge 500\]
Oh so.. 102(1)+150m+41≥500?
yep, now solve for m
119/50?
119/50 = 2.38 so you should find that m >= 2.38
the restrictions on m are that `0 <= m < 4` so together we know `0 <= m < 4` and `m >= 2.38` you can pick any number for m that makes BOTH of the inequalities shown above to be true
for example, you can pick m = 3 since it makes `m >= 2.38` true. Three is larger than 2.38 m = 3 also makes `0 <= m < 4` true because 3 is between 0 and 4
There are infinitely many values of m to pick here
oh ok, so (3,4) would be a ordered pair for part A?
does 4 have to be one of the numbers in the ordered pairs?
well recall that we made c = 1 so the first coordinate should be 1
IF you picked m = 3, then one of the solutions would be (1,3)
oh ok... how would I get the other two ordered pairs?
repeat the whole process over again but pick another value of c, say c = 2
you can do this just as long as c is between 0 and 8 (excluding 8)
oh ok, and the other number can't be more than 4?
or smaller than 0 based on the inequality 0 <= m < 4
102(2)+150m+41≥500 --- M>= 1.7 --- m=2 -- Ordered pair = (2,2) 102(5)+150m+41≥500 --- M>=0.34 --- m=1 -- ordered pair=(5,1)
@jim_thompson5910 is that the right way?
let me check
ok
I agree with the first one, but the second one I'm getting m >= -0.34 I would use c = 3 instead of c = 5
okay so, 102(3)+150m+41≥500 -- M>= 1.02 --- m= 3-- ordered pair = (3,3) ?
much better
so 3 solutions, of infinitely many, could be (1,3) (2,2) (3,3)
okay!! thank you sooo very much!! you're amazing!!
you're welcome
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