Question

A body of weight 200 newton falls from the height of 15 m and penetrate 2 cm into sand.

What average force is exerted on it by the sand, neglect air fraction.

Answer 1

here, the work done by the average force \(R\), has to be equal to the potential energy of the falling object, so we can write this equation:
\[\Large mgh = Rd\]
where \(d=2\) cm= \(0.02\) meters. So, we can write this:
\[\Large R = \frac{{mgh}}{d} = \frac{{Ph}}{d} = \frac{{2000 \cdot 15}}{{0.02}} = ...?\]