Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (iwanttogotostanford):

What

OpenStudy (nuttyliaczar):

Judging by the lack of information on phases given, I assume you need to understand a property of phase change. While phase is changing, temperature is not changing. I'm guessing the graph gives all three phases like this. Going off of that, what section of the graph is the solid phase?

OpenStudy (iwanttogotostanford):

600-1000 looks like it to me

OpenStudy (nuttyliaczar):

That's a phase change part of the graph because temperature is not rising as we add more heat

OpenStudy (iwanttogotostanford):

oh ok, I am not completely sure which would be the solid phase then....

OpenStudy (iwanttogotostanford):

200-400?

OpenStudy (nuttyliaczar):

While the line is sloping diagonally it is in a phase. While it is horizontal it is changing phase. Look at the diagonal parts.

OpenStudy (iwanttogotostanford):

oh, 1000-1200

OpenStudy (nuttyliaczar):

There are three sets of diagonal lines, and that is the rightmost one so it's probably the gas phase

OpenStudy (nuttyliaczar):

Solid is the coldest phase, where would that be?

OpenStudy (iwanttogotostanford):

oh ok! So how would i figure out the specific heat?

OpenStudy (nuttyliaczar):

Do as the units tell you. This is why units are so important in physics. Specific heat is the amount of heat needed to raise the temperature by one degree Celsius per unit mass

OpenStudy (iwanttogotostanford):

im not quite sure, i had trouble with the lesson now i have homework could you help please?:-)

OpenStudy (nuttyliaczar):

Unit mass is in grams, and this chart is given in terms of some substance of 20g. So divide the joules per degree by 20

OpenStudy (nuttyliaczar):

First off you know which section is the solid phase right?

OpenStudy (iwanttogotostanford):

no :-(

OpenStudy (nuttyliaczar):

What's the coldest part of the graph that is also diagonal?

OpenStudy (iwanttogotostanford):

0-200 added heat

OpenStudy (nuttyliaczar):

Yes, you can see why that's solid right? After I explained the phase shift property to you

OpenStudy (iwanttogotostanford):

yes! thanks :-)

OpenStudy (nuttyliaczar):

So during that phase what is the total change in joules?

OpenStudy (iwanttogotostanford):

4 J i got

OpenStudy (iwanttogotostanford):

since 200 divided by 20 is 4

OpenStudy (nuttyliaczar):

Did you remember to check the change in degrees?

OpenStudy (iwanttogotostanford):

change in degrees is 50 from 0-200

OpenStudy (nuttyliaczar):

How much did the temperature change during that heat added?

OpenStudy (nuttyliaczar):

Yes so remember this is per degree. What do you do with that information?

OpenStudy (iwanttogotostanford):

divide it by 200 since that is change in heat added

OpenStudy (nuttyliaczar):

Oh wait you divided wrong. 200 by 20 is 10

OpenStudy (iwanttogotostanford):

but 200 divided by 50 is 4

OpenStudy (nuttyliaczar):

So you have 10 now. That means it takes 10 joules per gram to do that temperature change of 50 degrees. So how much per degree?

OpenStudy (nuttyliaczar):

And yes you can do it that way too. 200 divided by 50 is 4, then divided by the total grams

OpenStudy (nuttyliaczar):

Math doesn't care what you divide by first

OpenStudy (iwanttogotostanford):

so now I would divide 4 by what??

OpenStudy (nuttyliaczar):

Total grams

OpenStudy (nuttyliaczar):

Look at the units. J/g*C

OpenStudy (nuttyliaczar):

Divide joules by total grams and change in temperature. And there's your answer

OpenStudy (iwanttogotostanford):

so 200 divided by 4??! I m so lost with this last part ugh

OpenStudy (iwanttogotostanford):

:-/

OpenStudy (nuttyliaczar):

One step at a time. I told you to divide by 20 and 50. Why did I tell you to divide by those?

OpenStudy (iwanttogotostanford):

because that is heat added divided by temperature

OpenStudy (nuttyliaczar):

Yes that explains the 200/50. But why also divide by 20?

OpenStudy (iwanttogotostanford):

because that is the amount of grams

OpenStudy (nuttyliaczar):

Yes, since specific heat is change in joules per gram per degree

OpenStudy (nuttyliaczar):

Now do you understand?

OpenStudy (iwanttogotostanford):

yes

OpenStudy (iwanttogotostanford):

but i still do not know how to get the Final answer

OpenStudy (nuttyliaczar):

Literally just that. Divide

OpenStudy (iwanttogotostanford):

i did and i got 2.5

OpenStudy (nuttyliaczar):

200/50 is 4, 4/20 is .2

OpenStudy (iwanttogotostanford):

i was doing 20 divided by 50 sorry..... I get it now i was being stupid

OpenStudy (iwanttogotostanford):

thank you for all of your help and i am sure you wouldn't want to help me with another hah!! :-)

OpenStudy (nuttyliaczar):

You just need to think about why you're doing what you're doing. It's not random, everything has a reason

OpenStudy (iwanttogotostanford):

true, thank you! Anyone willing to help me with another haha:-(

OpenStudy (nuttyliaczar):

Once again I'll see if I can

OpenStudy (iwanttogotostanford):

ok , will post another. thanks!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!