Question

I am trying to learn graphing for me to get smarter and smarter and this was my stop point where I just can't get it. If someone could explain to me how to do this. I will give you a medal,fan, and fan testimonial.

Answer 1

@mathmale

Answer 2

I'd like to help, but you'll need to postpone your question / problem first.

Answer 3

well I just can't understand like graphing things i.e (rise over run) I get it mixed up where I do (run over rise). Also I get mixed up with my quadrants if someone could explain that to me it would be helpful and maybe a way to memorize it.

Answer 4

also with Y and X intercept.

Answer 5

@ganeshie8

Answer 6

@imqwerty

Answer 7

@Mehek14

Answer 8

@♪Chibiterasu |

Answer 9

alright lets take an example and then graph it :)

Answer 10

okay lets start with this -
\(x+y=1\)

Answer 11

what do you think the graph of this equation will look like? :)
a line
a circle
a parabola
something else

Answer 12

something else?

Answer 13

cause a parabola is when x = 0 and y = 0 right?

Answer 14

a line wouldn't really be something that equals one. When you add y + x

Answer 15

and a circle I really don't think it would be

Answer 16

am I correct?

Answer 17

hello? Is anyone there?

Answer 18

@Michele_Laino

Answer 19

is anyone there?

Answer 20

@ganeshie8

Answer 21

@undeadknight26

Answer 22

You're asking to be taught a pretty broad concept. The fact you didn't recognize x+y=1 as a linear equation means you should probably start a bit more basic. Maybe something like Khan academy:
Maybe this
https://www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-linear-equations-functions/8th-solutions-to-two-var-linear-equations/v/descartes-and-cartesian-coordinates
Or slope
https://www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-linear-equations-functions/8th-slope/v/slope-intuition-example

Answer 23

yea I learned a little bit more from watching it

Answer 24

maybe you can test me on something

Answer 25

@inkyvoyd

Answer 26

@ganeshie8 @DanJS @tkhunny @TheSmartOne

Answer 27

@agent0smith reveal yourself

Answer 28

You were here for like 30 minutes and never was typing

Answer 29

It was probably a glitch in OS.

But I already posted what you should do. OpenStudy is better used as a place to enhance things you know, not learn an entire topic (unless it's something small/short).

Answer 30

Lima, great that you're eager to learn and want to start with graphing. You did well mentioning two subtopics of graphing right up front (rise over run = slope of a straight line, and quadrants) on which you wanted to focus. Best to spend sufficient time on those topics so that you gain at least a basic understanding of them BEFORE moving on to other topics. If you keep on adding topics you want to learn, other users stop answering you because few have time to explain entire topics at once.

So, back to the drawing board, so to speak. The slope of a straight line is defined as "rise over run," which is often written as m = slope = rise / run, or m= (change in y) over (change in x).

A horizontal line has a slope of zero, as the graph neither increases nor decreases as you increase x.

A slant line with a slope of m = 1 / 1 increases by exactly the same amount as x increases: