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Mathematics 10 Online
OpenStudy (iwanttogotostanford):

science/STEM

OpenStudy (raffle_snaffle):

um what is the equation again? I need to see the equation in order to help you.

OpenStudy (raffle_snaffle):

is it q = mc*deltaT?

OpenStudy (raffle_snaffle):

I believe so

OpenStudy (raffle_snaffle):

so we have everything here... m = mass c = specific heat t_o and t_f are given as well

OpenStudy (raffle_snaffle):

deltaT = Tf - Ti so what is Ti?

OpenStudy (raffle_snaffle):

Ti = t_o

OpenStudy (iwanttogotostanford):

@jim_thompson5910

OpenStudy (iwanttogotostanford):

@AihberKhan

OpenStudy (iwanttogotostanford):

@zepdrix

OpenStudy (aihberkhan):

Okay. So The equation is \(Q = mCp(deltaT) \) We already know that \(Q\) = heat required \(m\) = mass of silver = 24.7 kg (given) \(Cp\) = specific heat = 236 J/kg-C (given) \(delta~ T\) = temperature change = 30 - 14 = 16 C Now we just want to substitute the values. So can you solve this: \(Q = 24.7*236*16 \). What do you get? @iwanttogotostandford

OpenStudy (aihberkhan):

@iwanttogotostanford

OpenStudy (iwanttogotostanford):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

now just convert `93267.2` to scientific notation

jimthompson5910 (jim_thompson5910):

Something like `5.93 E 4 J` means `5.93 * 10^4 joules` 5.93 * 10^4 = 59,300 notice how the decimal point moved 4 spots to the right and how the exponent is +4

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