As a punishment for something naughty that we did, my little brother and I have to whitewash both sides of a fence. We start at the same time, and we each work at a constant rate. If we each whitewash one side, I'll finish in $2$ hours and my brother will finish in $3$ hours. But I'm a nice kid, so after I finish my side, I go around to the other side and help my brother finish his side. From the time I start helping him, how many minutes does it take us to finish the job? (Just ANSWER)
We can't just answer the question. It's against the Code of Conduct that we all agree to upon signing up. It is punishable by banning. However, I can assist you but I need you to work with me. Where do you think you should start?
Ok assigning variables?
That should work, however the dollar signs are throwing me off. Are we talking about a length is time, or price per hour?
length of time
Alright, where should the variables go?
you would use 2x and 3x
Then...........................
so 2x + 3x = x (I'm pretty sure)
that doesn't make sense srry
I use the idea of rate * time = 1 job and rate is in terms of "jobs per hour" and time is in hours
In this problem I would call the job "paint 1 side" and the rates are \[ my\ rate = \frac{1 \ side}{2 \ hours} \\ brothers \ rate = \frac{1 \ side}{3 \ hours} \] after I finish my side. when does that happen? You should expect 2 hours, but using the equation \[ rate \cdot time = 1 \ side\\ \frac{1}{2}\cdot t = 1 \\ t= 2 \ hours\] just to show how to do it that way. Meanwhile, the other guy did some work. How much did he do in 2 hours? Using his rate we get \[ \frac{1}{3} \cdot 2 = \frac{2}{3} \ side\] He painted ⅔ of a side and there is ⅓ of a side go go.
working together, they have to finish ⅓ of a side \[ \frac{1}{2} t + \frac{1}{3} t = \frac{1}{3} \] Can you finish to find t in hours? From the time I start helping him, how many minutes does it take us to finish the job? then change that into minutes
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