Question

@Michele_Laino

Answer 1

hint:
we have a right isosceles triangle, so we can write:
\(\sqrt 2=y\)

Answer 2

after that I apply the theorem of Pitagora, so I can write this:
\[\Large {x^2} = {y^2} + {2^2}\]

Answer 3

more precisely I meant that we have a isosceles right triangle

Answer 4

Alright

Answer 5

so, what is the right option?

Answer 6

Option D

Answer 7

that's right!! :)

Answer 8

@Michele_Laino

Answer 9

here, we have a \(30-60-90\) triangle, so we have:
\[y = \frac{{10}}{2} = ...?\]
then, in order to find \(x\), I apply the theorem of Pitagora:
\[{x^2} + {y^2} = {10^2}\]

Answer 10

5

Answer 11

ok! And what is \(x\) ?

Answer 12

hint:
we can write this:
\[\Large \begin{gathered}
{x^2} + {y^2} = {10^2} \Rightarrow {x^2} = {10^2} - {y^2} = 100 - 25 = 75 \hfill \\
\hfill \\
{x^2} = 75 \Rightarrow x = \sqrt {75} = \sqrt {25 \times 3} = \sqrt {{5^2} \times 3} = ...? \hfill \\
\end{gathered} \]

Answer 13

8.660

Answer 14

correct! :) Better is \(x= 5 \times \sqrt 3\)

Answer 15

so, what is the right option?

Answer 16

A

Answer 17

that's right!