Use the explicit formula an = a1 + (n - 1) • d to find the 350th term of the sequence below. 57, 66, 75, 84, 93, ... A. 3234 B. 3207 C. 3141 D. 3198
that type has terms that increase linearly, the same amount each time 'd'
you know the start term, and the difference to the next 'd', that is all you need
hint: the constant \(d\) of the series, is such that: \[d = 93 - 84 = 84 - 75 = 75 - 66 = 66 - 57 = ...?\]
an = a1 + (n - 1) • d n starts at 1, and results in a1, then every next term adds on an additional 'd' , any number term you want to know, it is just the first term value a1, and one less than the term number times the common difference 'd'
a1 + (n-1) d /. { a1 -> 57, n -> 350, d -> 66-57 } /. means apply the replacement rules on the right to the expression on the left and then evaluate the result. What looks like mumbo jumbo on the right hand side is a list of replacement rules from the Mathematica computer program. /. is the Mathematica replacement operator. Did you get 3198 ?
Yes thanks @robtobey @DanJS
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