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Mathematics 17 Online
OpenStudy (adamaero):

Math-physics problem about Gauss' Law http://assets.openstudy.com/updates/attachments/53052cace4b022471a64b0f4-munkeyman1985-1392848082760-gausslaw.pdf First question please

OpenStudy (adamaero):

E = q_enclosed/(A*ε_0) or E = kq/r

OpenStudy (michele_laino):

here we have to apply this form of the Gauss theorem: \[\Large \Phi \left( {\mathbf{E}} \right) = \frac{Q}{{{\varepsilon _0}}}\]

OpenStudy (michele_laino):

the flux has to be computed on a sphere whose radius is equal to \(8.1\) cm

OpenStudy (adamaero):

not a cylinder?

OpenStudy (michele_laino):

I think no, since the electric field is generated by a charge on a spherical conductor

OpenStudy (adamaero):

2*9ee9(.02^2-.048^2) --------------------divided by pi*(.081)^2 but isn't something wrong with that above?

OpenStudy (michele_laino):

the trial charge has to be placed at point P, outside the spherical shell, so the requested field, has the subsequent \(x-\)component: \[\Large E = \frac{1}{{4\pi {\varepsilon _0}}}\frac{Q}{{{r^2}}} = 9 \cdot {10^9} \cdot \frac{{\left( {1.4 - 8.1} \right) \cdot {{10}^{ - 6}}}}{{{{\left( {8.1 \cdot {{10}^{ - 2}}} \right)}^2}}} = ...\frac{N}{C}\]

OpenStudy (adamaero):

what about the point charges?

OpenStudy (michele_laino):

it is not necessary to know the magnitude of the trial charge

OpenStudy (adamaero):

Isn't the equation \[9*10^{9}(1.4-8.1)*10^{-6}/(4\pi8.1^{2})\] ?

OpenStudy (adamaero):

wait, with epsilon nought in the bottom?

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