Question

AP calc help
please help me. I give medals

Answer 1

@Loser66

Answer 2

@kropot72 @mathstudent55

Answer 3

Has the function done ANY decreasing on [0,5]?

Answer 4

the f(x), seems that from (0,2) it was decreasing

Answer 5

@tkhunny , from 0,2, the slope is constant and positive, meaning that f(x) was positive

Answer 6

There is no time in [0,5] when f'(x) < 0.

Answer 7

One way to solve this is to sketch f(x). This will give an estimate of the absolute minimum value of f(x) over the stated interval.

Answer 8

Im confused because I don't know how a constant positive slope in f' looks in f

Answer 9

It is a straight line with a slope of 2 between f(2) and f(4).

Answer 10

The answer is 3.

Answer 11

I got that for the x value, but not for the f(3) value.

Answer 12

Can you fill in between f(0) and f(2)?

Answer 13

Over the interval [0, 5], the graph f`(x) has all positive y-values, therefore the function f(x) is increasing over that interval. The rate at which it increases may differ, but it's always increasing. The lowest value for f(x) would then be at the lowest x-value. If you take the f`(5) - the integral of f`(x) from [0, 5], you get the value of f(0) or the relative minimum.

Answer 14

Be careful when looking at graphs of the derivative versus graphs of the function. The y-values of the derivative are the slope of the function, so if you are analyzing the function given its derivative, the rate of increase of the y-values on the derivative graph are not pertinent, usually.

Answer 15

On the gradient function at x = 0 where the gradient is zero, f(x) has a point of inflection.