For f(x) = esin(x) use your graphing calculator to find the number of zeros for f '(x) on the closed interval [0, 2π].

a.1
b. 2
c. 3
d. 4

Question

For f(x) = esin(x) use your graphing calculator to find the number of zeros for f '(x) on the closed interval [0, 2π]. 

a.1 
b. 2 
c. 3 
d. 4

aryana_maria2323 · Answer

Can you please help? @123AB456C @tkhunny @zepdrix

tkhunny · Answer

It's not clear what is wanted.  Your level of study seems to require you to learn a little LaTex in order to communicate a little better.

Do you mean $f(x) = e^{\sin(x)}$

You have to find a way to express what you need.

aryana_maria2323 · Answer

Yes that is exactly what I mean.

aryana_maria2323 · Answer

Can you help? @zepdrix

anonymous · Answer

it says use a calculator right?

anonymous · Answer

$$f(x)=e^{\sin(x)}$$
$$f'(x)=\cos(x)e^{\sin(x)}$$ by the chain rule

anonymous · Answer

$$e^{\sin(x)}$$ is never zero, so $$\cos(x)e^{\sin(x)}$$ is zero  only where cosine is zero

aryana_maria2323 · Answer

Yes. I put it in a graph but I don't understand this part [0,2pie]

aryana_maria2323 · Answer

Why are you putting cos in front of it?

anonymous · Answer

for which two values of $x$ in $[0,2\pi]$ is cosine equal to zero?

anonymous · Answer

it does say " find the number of zeros for f '(x)" right?
so step one is to find $f'$

aryana_maria2323 · Answer

Yes, Okay I will find the that. One second.

anonymous · Answer

...

aryana_maria2323 · Answer

Okay so when I put that into the graph I got 1

anonymous · Answer

whoa hold the phone
what did you get for the derivative

anonymous · Answer

just asking because 1 is certainly not the answer

aryana_maria2323 · Answer

I got e^sin(x) cos^2(x)-e^sin(x) sin(x)

aryana_maria2323 · Answer

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