Mathematics
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OpenStudy (iwanttogotostanford):
COnfused a bit plz help
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OpenStudy (iwanttogotostanford):
@mathstudent55
OpenStudy (smartanne):
I can help
OpenStudy (iwanttogotostanford):
@563blackghost by which number on the other side?
OpenStudy (iwanttogotostanford):
oh ok so now what was once x^2 is now just 9?
OpenStudy (iwanttogotostanford):
@563blackghost
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OpenStudy (iwanttogotostanford):
hello??? you were just here...
OpenStudy (iwanttogotostanford):
@563blackghost
OpenStudy (iwanttogotostanford):
@YoungStudier @jigglypuff314
OpenStudy (iwanttogotostanford):
@meeep
OpenStudy (iwanttogotostanford):
@K12IsAwesome
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563blackghost (563blackghost):
Im sorry but I do not know how to solve this...I was just responding on how to similify a variable by the power of 2...
OpenStudy (iwanttogotostanford):
@triciaal please help?:-)
OpenStudy (iwanttogotostanford):
@XhawaiiangirlX
OpenStudy (iwanttogotostanford):
@agent0smith
OpenStudy (iwanttogotostanford):
@AndrewIsHere @richgall____ @JJ_Diamond
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OpenStudy (xhawaiiangirlx):
okay so is this a two part question
OpenStudy (iwanttogotostanford):
yes
OpenStudy (welshfella):
note that both the expressions in x are equal to y
so by the transitive property of equality
-x^2 + 4 = 2x + 1
OpenStudy (welshfella):
you now have a quadratic equation
rearranging we get
x^2 + 2x - 3 = 0
can you solve this for x?
OpenStudy (iwanttogotostanford):
so for the solutions i used the quadratic equation and got {1 and -3}
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OpenStudy (iwanttogotostanford):
would that be my final result?
OpenStudy (iwanttogotostanford):
@welshfella
OpenStudy (welshfella):
those are the 2 possible values of x
to find the corresponding values of y just plug in 1 and -3 into the first original equation and work out y
OpenStudy (welshfella):
so one value of y would be - (1)^2 + 4 = -1+4 = 3
so one of the soltution sets is (1,3)
OpenStudy (welshfella):
find the other using x = -3
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OpenStudy (iwanttogotostanford):
i need to find the value for x now right?
OpenStudy (welshfella):
no - you need the value for y using x = -3
OpenStudy (iwanttogotostanford):
i plugged in (-3) to my original problem and I got 0...
OpenStudy (welshfella):
y = -(-3)^2 + 4 = -9 + 4 = ?
OpenStudy (iwanttogotostanford):
oh ok i got 1 now
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OpenStudy (welshfella):
so you can write the solution as
x =1 , y = 3
and
x = -3 , y = -5
or just (1,3) , (-3,-5)
OpenStudy (iwanttogotostanford):
ok, thank you! I get it now I had a brain fart for a moment haha- thanks for the help!
OpenStudy (welshfella):
yw
OpenStudy (iwanttogotostanford):
wouldn't the solution for the first one be {1,-3} thought?
OpenStudy (iwanttogotostanford):
because that is what i got when i plugged it into the quadratic equation I got 1 and then -3
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OpenStudy (welshfella):
No
- you can plug into the second equation if you like ( that would be easier!)
y = 2x + 1
y = 2(1) + 1 = 3
OpenStudy (iwanttogotostanford):
oh ok, i tried and got that too- thanks
OpenStudy (welshfella):
tyhe solutions correspond to 2 points on graph of the 2 equations
it might look something like
|dw:1454949757093:dw|