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Mathematics 14 Online
OpenStudy (iwanttogotostanford):

COnfused a bit plz help

OpenStudy (iwanttogotostanford):

@mathstudent55

OpenStudy (smartanne):

I can help

OpenStudy (iwanttogotostanford):

@563blackghost by which number on the other side?

OpenStudy (iwanttogotostanford):

oh ok so now what was once x^2 is now just 9?

OpenStudy (iwanttogotostanford):

@563blackghost

OpenStudy (iwanttogotostanford):

hello??? you were just here...

OpenStudy (iwanttogotostanford):

@563blackghost

OpenStudy (iwanttogotostanford):

@YoungStudier @jigglypuff314

OpenStudy (iwanttogotostanford):

@meeep

OpenStudy (iwanttogotostanford):

@K12IsAwesome

563blackghost (563blackghost):

Im sorry but I do not know how to solve this...I was just responding on how to similify a variable by the power of 2...

OpenStudy (iwanttogotostanford):

@triciaal please help?:-)

OpenStudy (iwanttogotostanford):

@XhawaiiangirlX

OpenStudy (iwanttogotostanford):

@agent0smith

OpenStudy (iwanttogotostanford):

@AndrewIsHere @richgall____ @JJ_Diamond

OpenStudy (xhawaiiangirlx):

okay so is this a two part question

OpenStudy (iwanttogotostanford):

yes

OpenStudy (welshfella):

note that both the expressions in x are equal to y so by the transitive property of equality -x^2 + 4 = 2x + 1

OpenStudy (welshfella):

you now have a quadratic equation rearranging we get x^2 + 2x - 3 = 0 can you solve this for x?

OpenStudy (iwanttogotostanford):

so for the solutions i used the quadratic equation and got {1 and -3}

OpenStudy (iwanttogotostanford):

would that be my final result?

OpenStudy (iwanttogotostanford):

@welshfella

OpenStudy (welshfella):

those are the 2 possible values of x to find the corresponding values of y just plug in 1 and -3 into the first original equation and work out y

OpenStudy (welshfella):

so one value of y would be - (1)^2 + 4 = -1+4 = 3 so one of the soltution sets is (1,3)

OpenStudy (welshfella):

find the other using x = -3

OpenStudy (iwanttogotostanford):

i need to find the value for x now right?

OpenStudy (welshfella):

no - you need the value for y using x = -3

OpenStudy (iwanttogotostanford):

i plugged in (-3) to my original problem and I got 0...

OpenStudy (welshfella):

y = -(-3)^2 + 4 = -9 + 4 = ?

OpenStudy (iwanttogotostanford):

oh ok i got 1 now

OpenStudy (welshfella):

so you can write the solution as x =1 , y = 3 and x = -3 , y = -5 or just (1,3) , (-3,-5)

OpenStudy (iwanttogotostanford):

ok, thank you! I get it now I had a brain fart for a moment haha- thanks for the help!

OpenStudy (welshfella):

yw

OpenStudy (iwanttogotostanford):

wouldn't the solution for the first one be {1,-3} thought?

OpenStudy (iwanttogotostanford):

because that is what i got when i plugged it into the quadratic equation I got 1 and then -3

OpenStudy (welshfella):

No - you can plug into the second equation if you like ( that would be easier!) y = 2x + 1 y = 2(1) + 1 = 3

OpenStudy (iwanttogotostanford):

oh ok, i tried and got that too- thanks

OpenStudy (welshfella):

tyhe solutions correspond to 2 points on graph of the 2 equations it might look something like |dw:1454949757093:dw|

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