**Chem 12 Question** I know [H3O +]= [OH-] in neutral water Considering the water is neutral (PH=7.000) ,Is it possible to add more acid to create a shift to the right to increase the concentration of [H3O+] and decrease the [OH-]? Ex. HCl + H20 --> H3O+ + cl-
Alright, let's say if we add more acid right? H3O+
[H3O+][OH-] are equal right? if we put in more acid. the acid is going to react with the OH so the OH- which is the base is going to pull off protons from the acid. what happens is we're going to have less OH which means that [OH-] goes down.
ok I get what you are saying. Is it also because of this? Kw= [H3O+][OH-] [OH-]= Kw/[H3O+] If we add more HCl , since it is strong acid. The [H30+] = [HCl], so more H30+. Therefore, the higher the value of H3O+ concentration at bottom. The lower the value of OH- concentration. Am I right?
Yes, @korosh23 in fact that's probably a better way to explain it. remember Kw [H+][OH-] = 1x10^-14 at 25 C so if we increase the concentration of H+ since we know that 1x10^-14 is a constant, the concentration of [OH] must go down.
Perfect. Thank you.
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