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Mathematics 10 Online
OpenStudy (ksaimouli):

One form to another! explain!!

OpenStudy (ksaimouli):

\[\frac{ 12 }{ z(2-z)(1+z) }\]

OpenStudy (misssmartiez):

does the bar stand for fractions or division.

OpenStudy (ksaimouli):

From that to this \[\frac{ 4 }{ z }(\frac{ 1 }{ 1+z }+\frac{ 1 }{ 2-z })\]

OpenStudy (ksaimouli):

Using partial fractions I don't see how they got that form

OpenStudy (misssmartiez):

Alright, hold on someone summoned me -.-' try to get other tutors while I help this girl.

zepdrix (zepdrix):

Well I guess you can do some fancy business like this:\[\large\rm \frac{12}{z(2-z)(1+z)}\quad=\quad \frac{4}{z}\left[\frac{3}{(2-z)(1+z)}\right]\]

zepdrix (zepdrix):

And then just apply Partial fractions to the bracketed portion.

OpenStudy (vuriffy):

@zepdrix I believe he constructed it correctly, with applied partial fractions shall be determined as the original equation you stated, @ksaimouli.

OpenStudy (ksaimouli):

lol, that's it! I did partial fraction for whole thing and got different answer

OpenStudy (vuriffy):

It happens, mate. Glad that someone was able to help you clear this up for you. (:

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