One form to another! explain!!
\[\frac{ 12 }{ z(2-z)(1+z) }\]
does the bar stand for fractions or division.
From that to this \[\frac{ 4 }{ z }(\frac{ 1 }{ 1+z }+\frac{ 1 }{ 2-z })\]
Using partial fractions I don't see how they got that form
Alright, hold on someone summoned me -.-' try to get other tutors while I help this girl.
Well I guess you can do some fancy business like this:\[\large\rm \frac{12}{z(2-z)(1+z)}\quad=\quad \frac{4}{z}\left[\frac{3}{(2-z)(1+z)}\right]\]
And then just apply Partial fractions to the bracketed portion.
@zepdrix I believe he constructed it correctly, with applied partial fractions shall be determined as the original equation you stated, @ksaimouli.
lol, that's it! I did partial fraction for whole thing and got different answer
It happens, mate. Glad that someone was able to help you clear this up for you. (:
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