Let f(x) = −4x + 7 and g(x) = 10x − 6. Find f(g(x)).
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OpenStudy (anonymous):
try it, i will check
OpenStudy (vuriffy):
You must have some knowledge of this topic, so at least attempt the problem. Satellite and I may help you in anyway possible to ensure you understand the concept.
OpenStudy (boldjon):
f(x) = -4x + 7
g(x) = 10x - 6
To get f(g(x)), simply replace the x in f(x) with g(x):
f(g(x)) = -4g(x) + 7
= -4(10x-6) + 7
= -40x + 24 + 7
OpenStudy (boldjon):
do the last part and that's yo answer :3
OpenStudy (vuriffy):
Boldjon, please give them a chance to attempt the question, but thank you for your help.
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OpenStudy (kaitlyn_nicole):
okay, i was thinking -4(10-6)+7
OpenStudy (boldjon):
hm... yeah that was close,
but the answer es
= -40x + 31
HARIBAAAA ur welcome
gtg :3
OpenStudy (kaitlyn_nicole):
so then you distribute, and get
-40x+31
OpenStudy (anonymous):
yeah but you need an \(x\) next to the \(10\)
OpenStudy (boldjon):
yes ur right :3
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OpenStudy (kaitlyn_nicole):
ooh ok
OpenStudy (anonymous):
not \[ -4(10-6)+7\] but rather \[ -4(10x-6)+7\]
OpenStudy (kaitlyn_nicole):
lright! so what happens when they give you an extra number;
for example:
Let f(x) = x − 2 and g(x) = x^2 − 7x − 9. Find f(g(−1)).
OpenStudy (anonymous):
it is actually easier, no algebra, just arithmetic
OpenStudy (kaitlyn_nicole):
when you get it would you just plug in the x to get a number?
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OpenStudy (anonymous):
first compute \(g(-1)\) what do you get?
OpenStudy (kaitlyn_nicole):
ummm, 1+7-9? is that what you meant??
OpenStudy (anonymous):
yes, for a grand total of?
OpenStudy (kaitlyn_nicole):
-1? oh what lol
OpenStudy (kaitlyn_nicole):
it equals the same?
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OpenStudy (anonymous):
yes -1
OpenStudy (anonymous):
now compute \(f(-1)\)
OpenStudy (kaitlyn_nicole):
-3?
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
so \[f(g(-1))=f(-1)=-3\] that is your answer
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OpenStudy (kaitlyn_nicole):
o wow! ill try one now
OpenStudy (anonymous):
k good
OpenStudy (kaitlyn_nicole):
Let f(x) = x + 8 and g(x) = x2 − 6x − 7. Find f(g(2)).
g(x)= 1
f(x)=10
so, f(g(2))=g(1)=10?
OpenStudy (anonymous):
i think your \(g(2)\) is wrong, but you have the right idea
OpenStudy (kaitlyn_nicole):
oh, oops!
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OpenStudy (kaitlyn_nicole):
i have one more question and that is it for functions!
OpenStudy (anonymous):
did you get the final answer to this one?
OpenStudy (kaitlyn_nicole):
10
OpenStudy (kaitlyn_nicole):
Let f(x) = 5x + 12. Find f−1(x).
we did one of these right?
OpenStudy (anonymous):
yes but we did it with numbers
now it is with variables
change x and y, solve \[x=5y+12\]for \(y\) in two steps
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OpenStudy (boldjon):
By f-1(x) you mean the inverse I assume. To do that just swap the values of your function with y<->x.
y=5x+12
becomes
x=5y+12
and now solve for y.
OpenStudy (boldjon):
if you had something like 1/5x - 12/5, that would be the closest
OpenStudy (kaitlyn_nicole):
ok so -12 + x=5y?
OpenStudy (anonymous):
yes that is step one
OpenStudy (kaitlyn_nicole):
both of you explaining is so difficult lol
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OpenStudy (kaitlyn_nicole):
ok! so would i divide by 5?
OpenStudy (anonymous):
eys
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
by divide, just write it
OpenStudy (kaitlyn_nicole):
so \[\frac{ x-12 }{ 5 }\]
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OpenStudy (anonymous):
bingo
OpenStudy (kaitlyn_nicole):
wooo thank you! I got a 90
OpenStudy (anonymous):
yay (i guess)
OpenStudy (anonymous):
100 would have been better
OpenStudy (kaitlyn_nicole):
yeah inknow! i got the 2nd to last one wrong
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OpenStudy (kaitlyn_nicole):
that my g(2) was messed up for something?
OpenStudy (anonymous):
prolly
OpenStudy (kaitlyn_nicole):
but i got the curriculum, so thank you for taking your time and explaining to it me