Question

@mathstudent55

Answer 1

This will regard to pythagorean theorem....we would input what we know...

\(\Large14^{2}+b^{2}=15^{2}\) we then simplify....

\(\Large\color{red}{196+b=225}\)....

We then subtract...\(\Large\color{green}{225-196=b}\)

Once you get this you will then square root the number to find a number that multiples itself...which would be in radical form....

Answer 2

sqrt 59

Answer 3

@Comrad do you agree?

Answer 4

I agree with what @563blackghost said however your answer is incorrect. Your simplification is flawed. I have no clue where you got 59 from. It is but simple subtraction.

Answer 5

Incorrect.

Answer 6

Ah, I see the problem... it should be sqrt 29

Answer 7

Correct ^^

Answer 8

Indeed!

Answer 9

Sorry about that guys :x

Answer 10

You're fine :)

Answer 11

We all make mistakes @shaleiah
One would never learn without their mistakes.

Answer 12

Its alright ^^ like @Comrad said "We all make mistakes"....

Answer 13

No

Answer 14

You have to square the numbers first.

Answer 15

@563blackghost
You're better at explaining things. c:

Answer 16

8^2+b=c^2
64+b=81
81-64=b

Answer 17

@Comrad

Answer 18

Sorry I got off after I had helped you @shaleiah....Your process is incorrect. We know both legs so we know \(\large{a}\) and \(\large{b}\)....so we substitute....

\(\Large9^{2}+8^{2}=c^{2}\) which we then simplify....

\(\Large\color{red}{81+64=c^{2}}\) We then add \(\large{81}\) and \(\large{64}\)....

\(\Large\color{green}{145=c^{2}}\) We now find the square root of \(\large{145}\)....

\(\Large\color{purple}{\sqrt{145}=c}\) Simplify to simplest radical form...