Question

Complex A: [Co(NO2)6]^3- P= 220000 cm^-1 DeltaOx= 29190cm^-2. Determine: Spin state (high or low) draw the d-orbital diagram to show the placement of electrons in the t2g and eg orbitals. Determine the CFSE (including P if needed) in kJ/mol. The conversion of wavenumbers (cm^-1) to energy is given by E= (N)(h)(c)(wavenumberS)

Answer 1

Could you post a picture or screen shot of this questions since when you copy and pasted this answer it doesn't make sense at all. Thanks
@IsTim

Answer 2

I haven't done this in a while but it's not too complicated.

First determine the electron count on the metal, and use the spectrochemical series (see link below) to determine whether it's high or low spin.

http://www.chm.davidson.edu/vce/coordchem/Ligands.html

Next, calculate the crystal field stabilization energy (first in wavenumber units) based on the configuration of the electrons into the d orbitals (high spin or low spin). Btw, did you copy down the units of \(\sf \Delta O_x\) correctly? I think it's supposed to be in "\(cm^{-1}\)".

see this link for more info http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch12/crystal.php

Use \(E=N*h*c\) which gives you the energy in J if you use the right units for speed of light and planks constant. Now you have CSFE in J.

Lastly find P, \(\sf P=((220000 cm^{-1})*h*c)-CSFE ~(in~J)\)