Question

1.

(3 pt)
Which is the direct linear variation equation for the relationship?

y varies directly with x and y = 10 when x = 2.


A.
y = 2x + 6

B.
y = 5x

C.
y = x – 8

D.
y = x + 8



2.

(3 pt)
Which is the quadratic variation equation for the relationship?

y varies directly with x2 and y = 72 when x = 6.


A.
y = x2 + 25

B.
y = 2x2

C.
y = 4x2

D.
y = 12x

Answer 1

Are you i K12

Answer 2

yes

Answer 3

I meant in k12

Answer 4

Sorry bad grammar

Answer 5

it is ok

Answer 6

i really need some help i just am stuck

Answer 7

i am stuck see i have bad grammer too.. lol

Answer 8

@pizza12 , @happy2behere , @AloneS , @Gabby2117 ,

Answer 9

hang on i will be right back

Answer 10

kk

Answer 11

direct linear variation can be expressed as \[y=kx\] where \(k\) is a constant.

you have a value of \(y\) and a value of \(x\). plug into that formula and solve for the value of \(k\).

Answer 12

quadratic direct variation is variation where \{y=kx^2\]and the approach is the same. plug in known point, solve for \(k\).

Answer 13

sorry, that should have been \[y=kx^2\] for quadratic...

Answer 14

what

Answer 15

if you have direct linear variation, you can write an equation \[y=kx\]where \(k\) is a constant known as the constant of variation.

you know a matching pair of values for \(x\) and \(y\) so put them in the formula \{y=kx\] and solve for the value of \(k\)