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3+(4x-5)=2/3(6x-3)
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\[3+(4x-5)=\frac{ 2 }{ 3 }(6x-3)\]
\[3+(4x-5)=\frac{ 2 }{ 3 }(6x-3)\] \[4x-2=4x-2\] \[0=0\] So that would be infinite solutions.
@Agl202 I know it's an infinite solution ,but HOW did you get that. That's what i'm asking
@dumbcow
:I
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3+(4x-5)=2/3(6x-3) So u will want to pull out like terms: 6x - 3 = 3 • (2x - 1) =(4x - 2) - 2 • (2x - 1) = 0 0=0 Does this make sense?
I'm guessing that was an equation looked up from the internet, I still don't get it though
can u do step by step explaining
@Agl202 explained it well enough. What else don't u get here? Simple.
@babeberry How did he/she get a 3? 6x-3 <<<
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"simple"
by pulling out like terms. duh
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