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Mathematics 7 Online
OpenStudy (anonymous):

3+(4x-5)=2/3(6x-3)

OpenStudy (anonymous):

\[3+(4x-5)=\frac{ 2 }{ 3 }(6x-3)\]

OpenStudy (agl202):

\[3+(4x-5)=\frac{ 2 }{ 3 }(6x-3)\] \[4x-2=4x-2\] \[0=0\] So that would be infinite solutions.

OpenStudy (anonymous):

@Agl202 I know it's an infinite solution ,but HOW did you get that. That's what i'm asking

OpenStudy (anonymous):

@dumbcow

OpenStudy (anonymous):

:I

OpenStudy (agl202):

3+(4x-5)=2/3(6x-3) So u will want to pull out like terms: 6x - 3 = 3 • (2x - 1) =(4x - 2) - 2 • (2x - 1) = 0 0=0 Does this make sense?

OpenStudy (anonymous):

I'm guessing that was an equation looked up from the internet, I still don't get it though

OpenStudy (anonymous):

can u do step by step explaining

OpenStudy (babeberry):

@Agl202 explained it well enough. What else don't u get here? Simple.

OpenStudy (anonymous):

@babeberry How did he/she get a 3? 6x-3 <<<

OpenStudy (anonymous):

"simple"

OpenStudy (babeberry):

by pulling out like terms. duh

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