Question

A particle moves along the x-axis with the position function s(t)= e^(cos(x)). How many times int he interval [0,2pi] is the velocity equal to 0?

Answer 1

velocity=(position)'

Answer 2

v(t)=s'(t)

Answer 3

so you need to solve s'(t)=0

Answer 4

in the given interval

Answer 5

I got more than 3 as my answer

Answer 6

more than three is one of my answer choices

Answer 7

can I see what equation you looked at ?

Answer 8

or at least your derivative

Answer 9

v(t) = ds/dt = e^cos(t) (-sin(t)) = 0

Answer 10

e^cos(t) will never be zero

you are basically being asked to solve sin(t)=0 on the interval [0,2pi]

Answer 11

I just noticed your problem switches t and x around a lot

Answer 12

anyways do you know how many times sin(t) is 0 in the interval [0,2pi]

Answer 13

you shouldn't get more than 3...

Answer 14

so sin(t)=0 when t is a multiple of pi

Answer 15

right...

Answer 16

0pi
1pi
2pi
anything else is outside the interval [0,2pi]

Answer 17

no

Answer 18

no?

Answer 19

I got just 3

Answer 20

that's right

Answer 21

thank you so much!!

Answer 22

0,pi,2pi are the only solutions such that v=0 in the interval [0,2pi]