John’s piggy bank contained 7 dimes and 3 quarters. He pulled out 1 coin without looking. Without replacing the first coin, John then pulled out a second coin.

What is the probability that both coins were dimes? Express your answer in simplest form.

Question

John’s piggy bank contained 7 dimes and 3 quarters. He pulled out 1 coin without looking. Without replacing the first coin, John then pulled out a second coin.
 
What is the probability that both coins were dimes? Express your answer in simplest form.

biue · Answer

its supposed to be a fraction as the answer, but I'm having trouble finding it out.

rebeccaxhawaii · Answer

okay so 7:3

biue · Answer

?

biue · Answer

@rebeccaxhawaii

biue · Answer

7/15/?!??!

rebeccaxhawaii · Answer

the chances of pulling 2 dimes is 2 out of 12 because there is 12 coins in all

rebeccaxhawaii · Answer

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sydniek17 · Answer

P(A)=dime on first try
P(B)=dime on second try

7 dimes+3 quarters=10 total coins
P(A)=7/10

Now there are only 6 dimes and 3 quarters, equaling 9 total coins.
P(B)=6/9=2/3

Since this is an "and" problem, we will multiply the two probabilities:
P(A)*P(B)
(7/10)*(2/3)=14/30
14/30 simplifies to your final answer of 7/15.