Question

WILL FAN AND MEDAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!

factor and check
a^7b^7+1

Answer 1

no answer choice

Answer 2

Nope

Answer 3

ok

Answer 4

here answer b = {-7, -5}

Answer 5

@-AngleWarrior-

Answer 6

\(\large a^7b^7+1?\)

Answer 7

yes

Answer 8

i gave u the answer

Answer 9

hmmm

Answer 10

or hm gimme a sec

Answer 11

Okay :)

Answer 12

1 + a7b7

Answer 13

\(\large {\textit{if "n" is an odd value then}
\\ \quad \\
a^{\color{brown}{ n}}+b^{\color{brown}{ n}}=(a+b)(a^{{\color{brown}{ n}}-1}-a^{{\color{brown}{ n}}-2}b^1+a^{{\color{brown}{ n}}-3}b^2\quad ...\quad -a^1b^{{\color{brown}{ n}}-2}+b^{{\color{brown}{ n}}-1})}\)

does that make any sense to you?
I assume you may have covered that, or your book should have it

Answer 14

well, \(\textit{if "n" is an odd value then}
\\ \quad \\
a^{\color{brown}{ n}}+b^{\color{brown}{ n}}=(a+b)(a^{{\color{brown}{ n}}-1}-a^{{\color{brown}{ n}}-2}b^1+a^{{\color{brown}{ n}}-3}b^2\quad ...\quad -a^1b^{{\color{brown}{ n}}-2}+b^{{\color{brown}{ n}}-1})\)

Answer 15

Yeah it makes since.

Answer 16

keeping in mind that \(\bf a^7b^7+1\implies (ab)^7+1\implies (ab)^7+1^7\)

recall that \(\bf 1^7 = 1\) thus

Answer 17

so.. there :), just factor that, and that'd give you 2 factors then