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Mathematics 14 Online
OpenStudy (hockeychick23):

Find the equation of a line that is perpendicular to the line x=4 and contains the point (-9,-8)

OpenStudy (ibbutibbu.):

Well, I would first graph those two things

OpenStudy (ibbutibbu.):

Actually, you take this @mathmale

OpenStudy (mathmale):

What is the slope of the line x=4? What is the slope of any line perpendicular to x=4?

OpenStudy (hockeychick23):

y=-1/4 ?

OpenStudy (mathmale):

Why y=-1/4? We're discussing slopes only.

OpenStudy (hockeychick23):

oh the slope of the line x=4 would be -1

OpenStudy (mathmale):

Could y ou defe nd that statement, please?

OpenStudy (hockeychick23):

yea you subtract x from both sides --> x-x= 4-x --> 0=-x+4

OpenStudy (mathmale):

Let's start over, please. What is the slope, if any, of the line x=4?

OpenStudy (hockeychick23):

1

OpenStudy (mathmale):

Not quite. What does the graph of the line x=4 look like?

OpenStudy (hockeychick23):

its a straight vertical line from 4 on the x axis

OpenStudy (mathmale):

a straight vertical line THROUGH

OpenStudy (mathmale):

x=4.

OpenStudy (mathmale):

How is the line x=4 related to the y axis?

OpenStudy (hockeychick23):

it isnt they never intersect

OpenStudy (mathmale):

Actually, there's a relationship. The line x=4 is _____________________ to the y-axis.

OpenStudy (hockeychick23):

parallel

OpenStudy (mathmale):

right. Next, what is the slope of a vertical line?

OpenStudy (hockeychick23):

y= -1/4

OpenStudy (mathmale):

That's a bit far off. How do you figure that a vertical line could have a slope of -1/4? Have you drawn the line x=4 yet?

OpenStudy (mathmale):

Slope = rise over run: rise / run

OpenStudy (mathmale):

Note: x=4 tells us that every point on this vertical line is at a distance of 4 units from the y-axis.

OpenStudy (hockeychick23):

yes |dw:1455065571612:dw|

OpenStudy (mathmale):

Nice graph. Same question: What is the slope of the vertical line x=4?

OpenStudy (mathmale):

If the line has a slope, you must be able to illustrate the rise and the run.

OpenStudy (hockeychick23):

ohh i think i got it the slope is -1, but the slope would be -1/8 for a perpendicular line

OpenStudy (mathmale):

Unfortunately, those two surmises are not correct. The slope of a vertical line is not -1. nor is the slope of a perpendicular line equal to -1/8.

OpenStudy (hockeychick23):

oh i took the y value and put it as 1/8 because its the negative reciprocal

OpenStudy (mathmale):

Look at your own drawing. Look at the vertical line thru x=4, described as x=4. What is an example of the rise? of the run? what is m = rise/ run? But, Chick, 4 is not a slope, and therefore you should not be taking the neg. recip. of it.

OpenStudy (mathmale):

Looking at the vertical line x=4, what is a sample rise? a sample run?

OpenStudy (mathmale):

\[slope=m=\frac{ rise }{ run }\]

OpenStudy (hockeychick23):

ohhh since its a distance of 4 units from the axis its -1/4

OpenStudy (mathmale):

a "rise" is a vertical change in positiion. a "run" is a horiz. change in position. Looking at the line x=4, do you see that x changes?

OpenStudy (hockeychick23):

no x doesnt change

OpenStudy (mathmale):

Concentrate solely on the vertical line x=4. Do you see x changing on that line?

OpenStudy (mathmale):

Then the horizontal change, or change in x, is zero. The vertical change, or change in y, could be any number. What is the value of 10 / 0?

OpenStudy (hockeychick23):

undefined

OpenStudy (mathmale):

Hint: "division by ____________ is undefined."

OpenStudy (mathmale):

Division by zero is undefined. Therefore, the slope of the vertical line x=4 is _________________________ ."

OpenStudy (hockeychick23):

undefined

OpenStudy (mathmale):

Correct. And what is the negative reciprocal of that? You know where the line x=4 is. Draw a horiz. line thru it for any y value you want.

OpenStudy (hockeychick23):

ok so i can pick a number and just say y= 1

OpenStudy (mathmale):

sure.

OpenStudy (mathmale):

draw the line y=1 on your previous graph.

OpenStudy (mathmale):

|dw:1455065974683:dw|

OpenStudy (hockeychick23):

|dw:1455066230191:dw|

OpenStudy (mathmale):

Good. Remembering that the line y=1 is horizontal, and that slope = rise / run, find the slope of the line y=1.

OpenStudy (hockeychick23):

0

OpenStudy (mathmale):

Exactly. The point-slope form of the eq'n of a str. line is \[y-y _{1}=m(x-x _{1})\] Please take the given point and subst. its coordinates into this equation of a line with slope m. In this case our slope, m, has the value _____ .

OpenStudy (mathmale):

The given point is (-9,-8).

OpenStudy (hockeychick23):

y+8=0(x+9) y+8=0 y=-8

OpenStudy (mathmale):

Super. Super. That's it. The line y=-8 is perpendicular to the vertical line x=4 and, additionally, it passes thru the given point (-9,-8).

OpenStudy (mathmale):

End of problem.

OpenStudy (hockeychick23):

ok thanks!!

OpenStudy (mathmale):

My pleasure. Review: The equation of the x-axis is _______________ The equation of the y-axis is ___________________ The line y=1 is _____________________ to the x-axis and _________________ to the y-axis.

OpenStudy (hockeychick23):

y=0 x=0

OpenStudy (mathmale):

Great. And the 2nd two blanks should read ________________ and __________________ .

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